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int xsin2x dx 01:37 int (2+3x)cos6x dx 02:38 int sec^3 x tanx dx 01:41 Evaluate the following integrals: int sin5x sin3x dx 01:27 int xsec^2 x dx 02:06 int xsin(x/4)cos(x/4)cos(x/2)dx 04:14 int xsin(x/2)cos(x/2)cosx dx 04:19 int xtan^2 x dx 02:27 ...
{ 0 } ^ { \frac { \pi } { 2 } } + \frac { 1 } { 2 } \int _ { 0 } ^ { \frac { \pi } { 2 } } \cos 2 x \\ = \frac { \pi } { 4 } + \frac { 1 } { 4 } \sin 2 x | _ { 0 } ^ { \frac { \pi } { 2 } } = \frac { \pi } ...
Answer to: Integrate using integration by parts \int \sin(2x)\sin(2x)dx By signing up, you'll get thousands of step-by-step solutions to your...
∴ \int _{ -1 }^{ 1 }( \sqrt {1-x^{2}}+\sin 2x)dx= \dfrac {π}{2}.故答案为: \dfrac {π}{2}.由和的积分等于积分的和展开,再由定积分的几何意义求解 \int _{ -1 }^{ 1 } \sqrt {1-x^{2}}dx,求出 \int _{ -1 }^{ 1 }\sin 2xdx,作和后得答案.本题...
Answer to: Evaluate \int \sin^2x \cos^4 x \, dx without using integral reduction. By signing up, you'll get thousands of step-by-step solutions...
But only those integrals can be transformed that is given in a form of {eq}\int f(h(x))h'(x)dx {/eq} Answer and Explanation: We have to solve the given indefinite integral {eq}\displaystyle \int e^{\sin^2(x)} \sin(2x) \ dx {/eq}. To evaluate the given integral that ...
【解析】 解: $$ 原式= \int 2 \sin x \cos xe^{- \sin x}dx \\ =- \int 2 \sin xd(e^{- \sin x}) \\ =-2e^{- \sin x}\sin x+2 \int e^{- \sin x}d(\sin x) \\ =-2e^{- \sin x}\sin x-2 \int e^{- \sin x}d1- \sin x) \\ =-2 \sin xe^{- \sin...
माना I=int(0)^(pi//4)sin 2x dx =int(0)^(pi//4)2sin x cos x dx माना sin x=t" "rArr" "cos x dx = dt x=(pi)/(4)" "rArr" "t=sin.(pi)/(4)=(1)/(sqrt2) x= 0 " "rArr" "t=sin 0 =0 therefore" "I=
【题目】用分部积分法计算下列定积分:$$ \int _ { 0 } ^ { \frac { \pi } { 2 } } $$xsin2xdx;