Integrate: intsinxcos2xsin3x\ dx 04:30 Evaluate: (i) int1/(sqrt(1+cos2x))\ dx (ii) int1/(sqrt(1-cosx))\ dx 04:13 Evaluate: (i) intsqrt((1-cos2x)/(1+cos2x))\ \ dx (ii) intsqrt((1+cosx)... 03:24 Evaluate: int1/(sqrt(1+sin2x))\ dx 04:37 Evaluate: int1/(...
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Find the indefinite integral. \int \frac {1}{36 + (x - 4)^2} dx Find the indefinite integral. \int (2 + x + 2x^2 + e^x)dx Find the indefinite integral. \int \frac{2x^ 7 - 5x^4 + 2}{x^7}dx Find the indefinite integral. \int \frac{1}{49+(x-9)^2}dx ...
But only those integrals can be transformed that is given in a form of {eq}\int f(h(x))h'(x)dx {/eq} Answer and Explanation: We have to solve the given indefinite integral {eq}\displaystyle \int e^{\sin^2(x)} \sin(2x) \ dx {/eq}. To evaluate the given integral that ...
∴ \int _{ -1 }^{ 1 }( \sqrt {1-x^{2}}+\sin 2x)dx= \dfrac {π}{2}.故答案为: \dfrac {π}{2}.由和的积分等于积分的和展开,再由定积分的几何意义求解 \int _{ -1 }^{ 1 } \sqrt {1-x^{2}}dx,求出 \int _{ -1 }^{ 1 }\sin 2xdx,作和后得答案.本题...
百度试题 结果1 题目求导:∫_0^(π/2)cos^2xsin2xdx\int _{0}^{ \dfrac{ \pi }{2}} \cos ^{5}x \sin 2xdx; 相关知识点: 试题来源: 解析 原式为一个常数,常数的导函数为0综上所述,结论为:0 反馈 收藏
किसी एक का मान ज्ञात करें: (i) intsin2x cosx dx" " (ii) int (cosx)/(cos(x+a))dx
সমাকলন করো : int cos^2x/sin^4x dx 01:23 সমাকলন করো : int sin^2theta/ ((1+costheta)^2)d theta 02:24 সমাকলন করো : int tan^3x dx 01:26 সমাকলন করো : int cot^4x dx 01:56 স...
Answer to: Integrate the indefinite integral.\int \sin^{2} x sin2x dx By signing up, you'll get thousands of step-by-step solutions to your...
百度试题 结果1 题目求\int_{}^{} {e^{-x}sin2x}\,{\rm dx} 相关知识点: 试题来源: 解析 ∫e^(-x)sinxdx=-∫sinxd(e^x)=-[sinx⋅e^(-x)-∫e^(-x)d(sinx)] 反馈 收藏