Solution intsin(2x)dx Hide Steps Solution steps One step at a time intsin(2x)dx Could not simplify further =intsin(2x)dx Solve instead intsin2(x)dx Examples x2−x−6=0 −x+3>2x+1 line(1,2),(3,1) ′ ∫ ∫ ∑
Evaluate intsin2xsin3x dxdot 03:28 Evaluate: inta^(m x)b^(n x)dx 02:12 Evaluate int(tanx)/(secx+tanx)dx 02:17 If int1/(x+x^5)dx=f(x)+c ,then the value of int(x^4)/(x+x^5)dxdot 03:25 If int((x^3+8)(x-1))/(x^2-2x+4)dx 01:42 Integrate the functions (...
Find value of int (ax+b)^(3//2) dx. 01:59 Find value of int (dx)/((ax+b)) . 01:38 Find value of int sin 2x dx. 03:49 Given , epsilon-L(di)/(dt)=iR, find the value of i at any time t in t... Text Solution Plot the line -3x-5y=15. 02:48 A particle starts...
设I=\(\int \sin\,x\,\cos\,x{dx},则I=\)() A. \(-\dfrac {1} {2}\sin^2x+C\) B. \(\dfrac {1} {2}\cos^2x+C\) C. \(\dfrac {1} {4}\cos\,2x+C\) D. \(-\dfrac {1} {4}\cos\,2x+C\) 相关知识点: 试题来源: 解析 D 反馈 收藏 ...
Answer to: Evaluate the integral \int \frac{9\cos x + \sin x}{\sin 2x} \,dx By signing up, you'll get thousands of step-by-step solutions to your...
百度试题 结果1 题目4.T2crc:π a.sin2xdxcostsintde 相关知识点: 试题来源: 解析 ∴I_1=110cm/htr 反馈 收藏
解:sin^2x=1-cos^2x=\dfrac{tan^2x}{1+tan^2x}原式=\int_{}^{} {\dfrac{1+tan^2x}{3+4tan^2x} }\,{\rm dx}=\dfrac{1}{3}\int_{}^{} {\dfrac{sec^2x}{1+\dfrac{2}{\root \of {3} } tan^2x} }\,{\rm dx}=\dfrac{1}{3}\cdot \dfrac{\root \of {3} }{2}\int_...
∫0π2sin2xdx的值是( ) A. 1 B. -1 C. 2 D. -2试题答案 在线课程 分析 找出被积函数的原函数,代入积分上限和下限计算即可. 解答 解:∫π20sin2xdx∫0π2sin2xdx=(-1212cos2x)|π200π2=1;故选A. 点评 本题考查了定积分的计算;关键是正确找出原函数.练习册系列答案 ...
\(∴ \int _{ -1 }^{ 1 }( \sqrt {1-x^{2}}+\sin 2x)dx= \dfrac {π}{2}\).故答案为:\( \dfrac {π}{2}\).由和的积分等于积分的和展开,再由定积分的几何意义求解\( \int _{ -1 }^{ 1 } \sqrt {1-x^{2}}dx\),求出\( \int _{ -1 }^{ 1 }\si...
int x*sin2x*cos2x*dx 04:32 Evaluate: int(cos2x+x+1)/(x^2+sin2x+2x)dx 02:39 Solve int(cos4x-cos2x)/(sin4x-sin2x)dx 03:36 int (sin2x+2)/(sin2x+cos2x+1) dx 08:44 int(sin2x)/(3-2 cos2x)dx 02:26 int(1)/(cos2x+sin2x)dx= 05:32 int(sin2x)/((1-cos2x)(2-co...