Find: int (sin2xcos2x)/sqrt(9-cos^4(2x))dx 05:35 int xsin2x dx 01:37 int (2+3x)cos6x dx 02:38 int sec^3 x tanx dx 01:41 Evaluate the following integrals: int sin5x sin3x dx 01:27 int xsec^2 x dx 02:06 int xsin(x/4)cos(x/4)cos(x/2)dx 04:14 int xsin(x/...
解 原式 $$ 式 = - \frac { 1 } { 2 } \int _ { 0 } ^ { \frac { \pi } { 2 } } x d \cos 2 x = - \frac { 1 } { 2 } x \cos 2 x | _ { 0 } ^ { \frac { \pi } { 2 } } + \frac { 1 } { 2 } \int _ { 0 } ^ { \frac { \pi }...
【题目】用分部积分法计算下列定积分:$$ \int _ { 0 } ^ { \frac { \pi } { 2 } } $$xsin2xdx;
Let I=int(0)^(pi) (x sin 2x "sin"((pi)/2cos x))/(2x-pi) dx………..1 Then I=int(0)^(pi)((pi-x)sin(2pi-2x)sin((pi))/2cos(pi-x))/(2(pi-x)-pi)dx =int(0)^(pi)((pi-x)(-sin2x)"sin"(-(pi)/2 cosx))/(pi-2x)dx, or I=int(0)^(pi)((x-pi)sin...
Answer to: Evaluate: int e sin2(x) sin(2x) dx By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can...
where {eq}u=g(x) {/eq} is the applied substitution. Answer and Explanation:1 We have to evaluate the following integral: $$\int \cos^2 x \sin 2x \, \mathrm{d}x $$ The method that we will use to evaluate the integral is the... ...
【题目】用分部积分法计算下列积分:1. xsin2xdx;2. ecosxdx;3.xe=dx;4. x^{2}arctanxdx;$$ 5 . \int x \ln
用分部积分法计算下列积分:1. xsin2xdx;2. ecosxdx;3.acedx;4. f$$ x ^ { 2 } $$arctanxdx$$ 5 . \int
sinxsin2xsin4x=sin3x. limx→0sin4x−sin2x+xx=? limx→0sin4x−sin2x+xx The range ofy=sin4x−sin2xsin4x+sin2xsatisfies View Solution প্রমাণ করো:∫cosxcos2xcos3xdx=14(x+sin2x24x4+sin6x6)+c যদি∫x ...
∫1+sin2x1+cos2xdx= View Solution ∫(2−sin2x1−cos2x)exdx= View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths DC Pandey Solutions for Physics ...