不定积分\(\int \ln(1 x^2) dx=\)() A. \(x\ln (1+x^2)+2(x-\arctan x)+C\) B. \(x\ln (1+x^2)-2(x-\arctan x)+C\) C. \(x\ln (1+x^2)-2(x+\arctan x)+C\) D. \(x\ln (1+x^2)+2(x-\arctan x)\) ...
解 首先证明对任意的$$ k > 0 , q \in R $$,有$$ \lim _ { x \rightarrow + \infty } \frac { x ^ { k } } { \ln ^ { q } x } = + \infty $$成立,显然,当 $$ q \leq 0 $$时,结论成立,当$$ q > 0 $$时,$$ \lim _ { x \rightarrow + \infty ...
Solution 1:∫01ln(1+x)1+x2dx=∫0π4ln(1+tanx)dx=∫0π4ln(1+tan(...
Answer to: Integrate: \\ \int \dfrac{\ln\sqrt{1 + x^2}}{x}dx By signing up, you'll get thousands of step-by-step solutions to your homework...
Answer to: Solve: \int^4_1 x^2ln(6x)dx By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can also ask...
1/2x dx 积分 为什么不是ln2x/2 而是lnx/2 是不是2 int 1/x dx 得出来的 那么ln2x/2和lnx/2是一样的吗
【解析】 $$ 2 \ln 2 - 1 $$ 结果一 题目 【题目】用Newton-Leibniz公式计算下列定积分∫_(-1)^1|x|dx 答案 【解析】∫_(-1)^1|x|dx=∫_(-1)^9-xdx+∫_0^1xdx=-1/2x^2|_(-1)^0+1/2x^2 或∫_(-1)^1|x|dx=2∫_0^1|x|dx=2∫_0^1xdx=x^2∫_0^1=1.(...
The value of the integral∫∞0xlogx(1+x2)2dxis View Solution View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
Answer to: Evaluate int from -ln 2 to 0 of 1/{1 + e^x} dx. By signing up, you'll get thousands of step-by-step solutions to your homework...
Find the indefinite integral, ∫1xlnx2dx. (Remember to useln(|u|) where appropriate. Integral: U-Substitution: The integrand involves a log term in the denominator. We can simplify this integral by a substitution. if we choose this log term as a ne...