{ \ln \ln x } { \ln x } | \cos 2 x d $$ 收敛,所以积分 $$ \int _ { 2 } ^ { + \infty } | \frac { \ln \ln x } { \ln x } \sin x | d x $$发散,即积分$$ \int _ { 2 } ^ { + \infty } \frac { \ln \ln x } { \ln x } \sin x d $$ ...
Answer to: Evaluate the integral \int (x + 2) \ln x \, dx By signing up, you'll get thousands of step-by-step solutions to your homework...
解析 【解析】 $$ \frac { \ln x } { 1 - x } + \ln | \frac { 1 - x } { x } | + C ; $$ 结果一 题目 1求下列不定积分:①f(2-x)dx 答案 解:J(2-xs+dx =号-(2-x)+C 结果二 题目 【题目】1求下列不定积分:①(2-x)dx 答案 【解析】 解:Jx2dx =号...
View Solution ∫x(logx)2dx View Solution ∫[logx−11+(logx)2]2dx = View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths DC Pandey Solutions for Physics ...
Integrate: {eq}\int \frac{dx}{x \ln x} {/eq} Integration By Substitution: If we have an integral in the form {eq}\int f(g(x))g'(x) dx {/eq}, then integration by substitution is the best method to solve this type of integral. ...
【解析】 $$ \int \frac { \ln x - 1 } { x ^ { 2 } } d x = \int ( \frac { \ln x } { x ^ { 2 } } - \frac { 1 } { x ^ { 2 } } ) d x = - \int \ln x d \frac { 1 } { x } - \int \frac { 1 } { x ^ { 2 } } d x \\ = -...
Evaluate the integral {eq}\int x\ln(x^2) \,dx {/eq} Integration By Parts: The derivative of the log function is a rational function. So by using integration by parts, we can convert the integral into a rational integral. We integrate the rational function by using the power rule. ...
【解析】 $$ I= \int _{0}^{2}\ln ^{2}xdx \\ =x|n^{2}x|_{0}^{e}- \int _{0}^{e}x \cdot 2 \ln x \cdot \frac{1}{x}dx \\ =e-2 \int _{0}^{e}\ln xdx \\ =e-2(x \ln x1_{0}^{e}-S_{0}^{e}x \cdot \frac{1}{x}dx) \\ =e-2e+...
int(xlnx)/((x^2-1)^(3/2))dx 04:33 int(e^(x))/((1+x)^(3))dx-int(e^(x))/(2(1+x)^(2))dx= 02:16 (i) \ int \ (x^3-1)/(x^2) \ dx quad (ii)int \ (x^(2//3)+1)dx 01:29 int(xlnx)/(x^(2)-1)^(3//2) dx equals 05:24 निमिन्...
Answer to: Evaluate the integral, and state whether the integral converges or diverges. int_{0}^{2} ln x/x dx By signing up, you'll get thousands...