【解析】 $$ 2 \ln 2 - 1 $$ 结果一 题目 【题目】用Newton-Leibniz公式计算下列定积分∫_(-1)^1|x|dx 答案 【解析】∫_(-1)^1|x|dx=∫_(-1)^9-xdx+∫_0^1xdx=-1/2x^2|_(-1)^0+1/2x^2 或∫_(-1)^1|x|dx=2∫_0^1|x|dx=2∫_0^1xdx=x^2∫_0^1=1.(...
∫π/20ln(sinx)dx=−π2ln2 ∫ ln(1+cosx) dx View Solution ∫ logx dx View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths DC Pandey Solutions for Physics ...
समाकलन int(-1/2)^(1/2)[[x]+ln((1+x)/(1-x))]dx बराबर है
解 首先证明对任意的$$ k > 0 , q \in R $$,有$$ \lim _ { x \rightarrow + \infty } \frac { x ^ { k } } { \ln ^ { q } x } = + \infty $$成立,显然,当 $$ q \leq 0 $$时,结论成立,当$$ q > 0 $$时,$$ \lim _ { x \rightarrow + \infty ...
Find the indefinite integral, ∫1xlnx2dx. (Remember to useln(|u|) where appropriate. Integral: U-Substitution: The integrand involves a log term in the denominator. We can simplify this integral by a substitution. if we choose this log term as a ne...
题目 【题目】不计算积分,比较下列积分大小.$$ \int _ { 1 } ^ { 2 } \ln x d x , \int _ { 1 } ^ { 2 } ( \ln x ) ^ { 2 } d x $$ 相关知识点: 试题来源: 解析【解析】 $$ \int _ { 1 } ^ { 2 } \ln x d x > \int _ { 1 } ^ { 2 ...
Answer to: Solve: \int^4_1 x^2ln(6x)dx By signing up, you'll get thousands of step-by-step solutions to your homework questions. You can also ask...
dxx 2 ln 解答: 令,xuln=xdxdvln= 則dx x du 1 =,xxxv−=ln () ∫ dxx 2 ln ()() ∫ −−−=dx x xxxxxxx 1 lnlnln利用分部積分法 ()() ∫ −−−=dxxxxxx1lnlnln求出() ∫ −dxx1ln=()xxxx+−ln
解析 【解析】 $$,解: \int1n(1+x)dx \\ =x \ln(1+x)- \int \frac{x}{1+x}dx \\ =x \ln(1+x)- \int \frac{1+x-1}{1+x}dx \\ =x \ln(1+x)- \int 1dx+ \int \frac{1}{1+x}dx \\ =x \ln(1+x)-x+1n(1+x)+c $$ (c为任意常数) ...
By applying a simple formula of integration we can solve the given integral. Answer and Explanation: Let: {eq}\displaystyle I=\int \frac{1}{(xsin^2(ln(x)))}dx {/eq} Let us substitute: {eq}lnx=t \\\displaystyle \frac{1}{x}dx=dt {/eq} {eq}\begin{......