分解因式:xy(x2−y2)+yz(y2−z2)+xz(z2−x2) .A.−(x+y+z)(x+y)(y−z)(z−x)B.−(x+y+z)(x−y)(y−z)(z+x
题目【题目】分解因式:xy(x2-y2)+yz(y2-z2)+zx(z2-2).A.(x+y+z)(x+y)(y-z)(z-x)B.(x+y+z)(x-y)(y-z)(z-x)C.-(x+y+z)(x-y)(y-z)(z-x)D.-(x+y+z)(x+y)(y-z)(z-x) 相关知识点: 试题来源: 解析 【解析】C ...
解析 xy(x2-y2)+yz(y2-x2+x2-z2)+zx(z2-x2) =(xy-yz)(x2-y2)+(yz—xz)(x2-z2) =(x-y)(x-z)(y(x+y)-z(x+z)) =(x-y)(x-z)(x+y+z)(y-z) 分析总结。 因式分解对称多项式扫码下载作业帮拍照答疑一拍即得答案解析查看更多优质解析举报xy...
xy(x2-y2)+yz(y2-z2)+zx(z2-x2)=x^3y-xy^3+y^3z-yz^3+z^3x-zx^3 =(y-z)x^3-(x-z)y^3+(x-y)z^3 =(y-z)x^3-(x-y+y-z)y^3+(x-y)z^3 =(y-z)(x^3-y^3)+(x-y)(z^3-y^3)=(x-y)(y-z)(x^2+xy+y^2-z^2-zy-y^2)=(x-y)(y-z)(...
答案解析 查看更多优质解析 解答一 举报 xy(x2-y2)+yz(y2-x2+x2-z2)+zx(z2-x2) =(xy-yz)(x2-y2)+(yz—xz)(x2-z2)=(x-y)(x-z)(y(x+y)-z(x+z))=(x-y)(x-z)(x+y+z)(y-z) 解析看不懂?免费查看同类题视频解析查看解答 更多答案(1) ...
=(xy-yz)(x²-y²)+(yz-zx)(x²-z²)=y(x-z)(x+y)(x-y)+z(y-x)(x+z)(x-z)=y(x-z)(x+y)(x-y)-z(x-y)(x+z)(x-z)=(x-y)(x-z)[y(x+y)-z(x+z)]=(x-y)(x-z)[(xy-xz)+(y²-z²)]=(x-y)(x-z)[x(y-...
=xy(x²-y²)-yz(x²-y²)+yz(x²-z²)-zx(x²-z²)=(xy-yz)(x²-y²)+(yz-zx)(x²-z²)=y(x-z)(x+y)(x-y)+z(y-x)(x+z)(x-z)=y(x-z)(x+y)(x-y)-z(x-y)(x+z)(x-z)=(x-y)(x-z)[y(x+y)-z(x+z)]=(x-y)(x-z)[(xy-xz)+...
(x2+y2+z2)(xy+yz+zx). 由因式定理可知,原式没有一次因式,故可设原式=[a(x2+y2+z2)+b(xy+yz+zx)][c(x2+y2+z2)+d(xy+yz+zx)],比对系数可知,xy(x2+y2)+yz(y2+z2)+zx(z2+x2)+xyz(x+y+z)=(x2+y2+z2)(xy+yz+zx).解题...
因式分解 xy-xz- y2 +2yz- z2 答案 原式=xy-xz-⎛ ⎛| || |⎝⎞⎟⎟⎠y2-2yz+z2=x⎛ ⎛| |⎝⎞⎟⎠y-z-⎛ ⎛| |⎝⎞⎟⎠y-z2=⎛ ⎛| |⎝⎞⎟⎠y-z⎛ ⎛| |⎝⎞⎟⎠x-y+z故答案为: ⎛ ⎛| |⎝⎞⎟⎠y-z⎛ ...
因式分解:xy−xz−y2+2yz−z2.a2−b2−x2+y2−2ay+2bx.x5−x4+2x3−2x2+x−1.a2x4+abx3+a2x2y+b2xy2+aby3−b2y4. 答案 (1)原式=(y−z)(x−y+z).(2)原式=(a−y+b−x)(a−y−b+x).(3)原式=(x−1)(x2+1)2.(4)原式=(ax2+by2)(ax...