LeetCode-Word Search 很简单的dfs; 1classSolution {2public:3boolexist(vector<vector<char> > &board,stringword) {4//Start typing your C/C++ solution below5//DO NOT write int main() function6if(word.empty()) {7returntrue;8}9if(board.empty()) {10returnfalse;11}12intm =board.size()...
题目地址:https://leetcode.com/problems/word-search/description/ 题目描述 Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where “adjacent” cells are those horizontally or vertically neighboring. The sam...
class Solution { public: bool exist(vector<vector<char>>& board, string word) { h = board.size(); w = board[0].size(); for(int i = 0; i < h; i++){ for(int j = 0; j < w; ++j){ if(searchexist(board, word, 0, i, j)) return true; } } return false; } int se...
[ ['A','B','C','E'], ['S','F','C','S'], ['A','D','E','E'] ] 1. 2. 3. 4. 5. 6. Given word = "ABCCED", return true. Given word = "SEE", return true. Given word = "ABCB", return false. 链接:https://leetcode-cn.com/problems/word-search 著作权归领扣...
/** @lc app=leetcodeid=212 lang=cpp** [212] Word Search II** https://leetcode.com/problems/word-search-ii/description/** algorithms* Hard (29.77%)* Likes: 1405* Dislikes: 78* Total Accepted: 132.7K* Total Submissions: 440.4K* Testcase Example: '[["o","a","a","n"],["e"...
class Solution{public:boolexist(vector<vector<char>>&board,string word){for(inti=0;i<board.size();i++)for(intj=0;j<board[0].size();j++)if(board[i][j]==word[0])if(backtrack(board,word,i,j,board.size(),board[0].size(),0,word.size()))returntrue;returnfalse;}private:boolbac...
https://zxi.mytechroad.com/blog/searching/leetcode-212-word-search-ii/ 复现: classSolution{private:classTrieNode{public:TrieNode(){}shared_ptr<string>word=nullptr;vector<shared_ptr<TrieNode>>next=vector<shared_ptr<TrieNode>>(26,nullptr);};vector<string>ret;introw,col;public:vector<string>...
leetcode hot 100——easy题(python) 题解思路主要来源于@灵茶山艾府。 1 两数之和 1.1 题目 给定一个整数数组 nums 和一个整数目标值 target,请你在该数组中找出 和为目标值 target 的那 两个 整数,并返回它们的数组下标。你可以假设每种输入只对应一个答案,但是数组中的同一个元素不能重复出现。你可以...
79. Word Search https://leetcode.com/problems/word-search/description/ Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where &...79. Word Search 注意传引用......
public class Solution { public boolean exist(char[][] board, String word) { for (int i = 0; i < board.length; i++) { for (int j = 0; j < board[0].length; j++) { if (board[i][j] == word.charAt(0)) { if (helper(i, j, 0, word,board) == true) { ...