Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are th...Leetcode 212. Word Search II Problem: Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of ...
for(inti=0;i<word.size();i++){ if(p->next[word[i]-'a'] == NULL) p->next[word[i]-'a']=newTrieNode(); p=p->next[word[i]-'a']; } p->isString=true; } // Returns if the word is in the trie. boolsearch(string word) { TrieNode* p=root; for(inti=0;i<word.siz...
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Leetcode212. Word Search II 题目题目链接思路将词典构建为Trie, 对board中的每个字母,进行dfs遍历,检查是否在Trie中复杂度设词典最长词的长度为L,board有M行N列时间复杂度 O ( n ) \mathcal{O}(n) O(n) 最坏情况,board中的每个字母,向四个方向都能不停的匹配下去,直到达到字典中的单词长度,如字典为...
Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be used more than once in a word. Example: Input: words = ["oath","pea","eat","rain"] and board = ...
}varchild =getChild(node, x, y)if(!child) {return}if(child.word!==null) { res.push(child.word); child.word=null} visited[x][y] =true;backtrack(child, x +1, y);backtrack(child, x -1, y);backtrack(child, x, y +1);backtrack(child, x, y -1); ...
LeetCode <bt>79&212 Word Search I&II 编程算法 Given a 2D board and a word, find if the word exists in the grid. 大学里的混子 2018/11/08 4680 Leetcode 79 Word Search cellexistsgridword Given a 2D board and a word, find if the word exists in the grid. The word can be construct...
LeetCode-212. Word Search II Given a 2D board and a list of words from the dictionary, find all words in the board. Each word must be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may ...
题目链接: https://leetcode-cn.com/problems/word-search-ii Given an m x n board of characters and a list of strings words, return all words on the board. Each word must be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertic...
示例2: 输入:board = [["a","b"],["c","d"]], words = ["abcb"]输出:[] 提示: m == board.length n == board[i].length 1 <= m, n <= 12 board[i][j]是一个小写英文字母 1 <= words.length <= 3 * 104 1 <= words[i].length <= 10 ...