题目地址:https://leetcode.com/problems/word-break-ii/ 题目解析:看到题目的第一思路是采用递归暴力解法,每找到一个单词将单词添加到返回的结果集中,并将查找的开始位置后移直到字符串的结尾。 题目解答: import java.util.HashSet; import java.util.LinkedList; import java.util.List; import java.util.Set...
A solution is ["cats and dog", "cat sand dog"].*/classSolution {public: vector<string> wordBreak(strings, unordered_set<string> &dict) { vector<string>retvec;if(s.size() ==0|| dict.size() ==0)returnretvec;intlen =s.size(); vector<bool> dp(len+1,false);//保存状态,dp[i]...
140. Word Break IIHard Topics Companies Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note that the same word in the dictionary may be reused ...
【Leetcode】Word Break II 题目链接:https://leetcode.com/problems/word-break-ii/ Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, given s = “catsanddog...
【Leetcode】Word Break 题目链接:https://leetcode.com/problems/word-break/ 题目: Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, given...
House Robber II - Dynamic Programming - Leetcode 213 呼吸的chou 0 0 Search in rotated sorted array - Leetcode 33 - Python 呼吸的chou 0 0 一次搞懂所有寻路算法:用最接地气的方式讲解 DFS、BFS、Dijkstra、A*,再也不怕迷路! simviso-cs 1843 0 Longest Common Subsequence - Dynamic Programming...
Return true because "leetcode" can be segmented as "leet code". ** My code: importjava.util.Set;publicclassSolution{publicbooleanwordBreak(Strings,Set<String>wordDict){boolean[]isBreakUp=newboolean[s.length()+1];isBreakUp[0]=true;for(inti=1;i<s.length()+1;i++){for(intj=0;j<i;j...
参考了Discuss区一个DFS+DP的解法(https://leetcode.com/problems/word-break-ii/discuss/44262/My-C%2B%2B-DP%2BDFS-solution-(4ms)),学到了一种新的剪枝策略: classSolution{private://DFS path build functionvoidbuildPath(boolisBreakable[],string&s,intpos,vector<string>&res,string curP,unordered_...
https://leetcode.com/problems/word-ladder/description/ Problem: Given two words (beginWord and endWord), and a dictionary’s word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word mus...
leet s[0:0+4] in wordDict s[0+4] = True l e e t c o d e T F F F T F F F F 当搜索到这里时会再次进行重复的搜索。 --- emmm, 写法待改进。 这个写法思路一样,不过效率会低。 beat 3%. 测试地址: https://leetcode.com/problems/word-break/description/ """ class Solution(...