出现"i is not a constant"（i不是一个常量）的错误是因为作者在索引表达式中使用了非常量的变量。
这个错误的直接原因是 Verilog 不支持 Data_i[i*8-1:i*8-8] 这种语法。如果把向量的位选取写成 v...
这个是用c语言写电路。那个for里面的i需要定义为genvar i；另外从你写的逻辑看，你是希望那个shift_reg不断的变化，但是你这么写的话。系统会认为是一个组合逻辑，所以会立刻计算出结果。你需要写成时续逻辑的电路，用always @（posedge clk）begin ...end ...
assign 不能放在if里，除非是generate if。如果用always，就不能用assign
Hello, I am trying to make a simple for loop to add up a parameterizable count of numbers, all in the same clock cycle( I am aware that this may
Error: Error (10734): Verilog HDL error at seg7_controller.v(82): avs_s1_address is not a constant File: f:/fpga/niosii_mpc/de3_seg/ip/seg7_controller/seg7_controller.v Line: 82 错误提示解释说avs_s1_address不是常值。代码可以修改为: ...
晕，你要给count赋值就要把count定义成reg型的，不能定义成integer（整数型），改成reg[31:0]count试试。
x.data[theword][thebyteH : thebyteL] = $urandom_range(0,255) ; 'this' is not an elaboration-time constant. To correct the error you may convert this const variable to a parameter or a localparam. The geometry of the data record, just a memory, is declared in the def...
(3) Referenced variable I_data is not in sensitivitylist (4) Latch generated from always block for signal 如果改always@(I_clock)为always@(posedgeI_clock)就可以避免,并产生一个带使能的DFF9. 下面逻辑有没有问题? moduledff_en(I_reset1,I_reset2,I_data,I_clock,O_data); inputI_clock; inp...
is high forces q to remain at 0. This condition may or may not be correct depending on the actual flip flop. However, this is not the main problem with this model. Notice that when reset goes low, that set is still high. In a real flip flop this will cause the output to go to ...