result[1] =jreturnresult[:]//返回结果} } }returnnil } 回到顶部 四、C代码 int* twoSum(int* nums,intnumsSize,inttarget) {int*a = (int*)malloc(2*sizeof(int));for(inti =0;i < numsSize;i++){for(intj = i +1;j < numsSize;j++){if(nums[j] == target -nums[i]){ a[0]...
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based. You may assume that each input would have exactly one solution. ...
因此我们可以用两个for循环遍历整个数组,找到这个数组中两个值的和等于这个给定值的数组下标并输出。 三、Go代码 AI检测代码解析 //1_常规解法 func twoSum(nums []int, target int) []int { var result = [2]int {0,0} if len(nums) < 2 { return nil } for i := 0 ; i < len(nums) - ...
可以参考这个链接: 求和问题总结(leetcode 2Sum, 3Sum, 4Sum, K Sum),写的很清楚。 这里我只写了2Sum和3Sum的代码,注意要避免重复排序,同时避免重复数字的循环。 代码如下: import java.util.ArrayList; import java.util.Arrays; import java.util.List; public class Solution { //javascript:void(0) //K...
Can you solve this real interview question? Two Sum - Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. You may assume that each input would have exactly one solution, and you may n
Leetcode Solutions(一) two-sum Two Sum 题目 给定一个整数数组和一个目标值,找出数组中和为目标值的两个数。 你可以假设每个输入只对应一种答案,且同样的元素不能被重复利用。 示例: 给定 nums = [2, 7, 11,…
当然可以for两次暴力搜索,比较快的解法就是设置一个空字典,遍历列表,看目标与当前遍历元素的差值是否在字典中,如果不在,就把当前元素值作为key当前元素索引作为value加入字典中。字典存储遍历过的值,当遇到可以配对的,直接从字典输出索引即可。如果最终补课配对,则字典中刚好存满了列表的值。
class Solution: def twoSum(self, nums: List[int], target: int) -> List[int]: hashtable = dict() for i, num in enumerate(nums): if target - num in hashtable: return [hashtable[target - num], i] hashtable[nums[i]] = i ...
[Two Sum Hash]"){Solution solution;SECTION("1"){vector<int>expected_result{0,1};vector<int>nums{2,7,11,15};vector<int>result=solution.twoSumWithHash(nums,9);REQUIRE(CompareVectors<int>(expected_result,result)==true);}SECTION("2"){vector<int>expected_result{1,3};vector<int>nums{2,...
Given an arraynumsofnintegers, are there elementsa,b,cinnumssuch thata+b+c= 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. 给定数组,找出其中不重复的三个和为0的元素集合。