leetcode刷题之two sums 1 问题叙述 Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may
//根据leetcode测试,在map里面找比在list找目标数字更快一些。 if (map.containsKey(toFind)) { return true; } } else { if (map.get(cur) > 1) { return true; } } } return false; } } 复杂度分析 这种题应该不太需要分析复杂度吧,能实现就行。每次都是遍历一遍List,所以就是O(n)。 最后再...
首先考虑到时间复杂度O(N^2)的循环遍历,leetcode不能忍。 第二种方案复杂度为O(N),遍历数组时,以数值为key,索引为value建立字典,然后每次target值减当前值从字典中获取index,index小于i则说明在字典中存在。 代码O(N^2) classSolution1:#@param {integer[]} nums#@param {integer} target#@return {integer...
sumsMap.insert(make_pair(one, group)); i++; }for(i =0; i < nums.size() -1; i++) {intvalueI =nums.at(i);intremain = target -valueI;if(sumsMap.find(remain) !=sumsMap.end()) { vector<int> vecj =sumsMap.at(remain);intlen =vecj.size();for(intj =0; j < len; j++...
这是每个初次接触leetcode的同学都将做的第一道题。题目本身的思维方式十分简单,可采用暴力破解法,利用for循环嵌套,便可通过测试: class Solution: def twoSum(nums: list, target: int) -> list: newlist = [] for firstIndex in range(0, len(nums)-1): for secondIndex in range(firstIndex+1, len...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
--| main.go (source file that will contain our solution) --| go.mod (automatically created when running go mod init) 而已! 无需疯狂地学习包、导入、外部依赖或与本文目标无关的任何内容。 在移动之前,让我们看一下运行 go mod init leetcode-go 后自动创建的 go.mod 文件的内容(顺便说一句,模块...
Question URL: https://leetcode.com/problems/two-sum/ Given an array of integersnumsand an integertarget, return indices of the two numbers such that they add up totarget. You may assume that each input would haveexactly one solution, and you may not use the same element twice. ...
target,whereindex1 must be less than index2.Pleasenote that your returned answers(both index1 and index2)are not zero-based.Youmay assume that each input would have exactly one solution and you may not use the same element twice.Input:numbers={2,7,11,15},target=9Output:index1=1,index2...
https://leetcode.com/articles/two-sum/#approach-2-two-pass-hash-table-accepted Question Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the ...