Define arctan. arctan synonyms, arctan pronunciation, arctan translation, English dictionary definition of arctan. maths abbreviation for 1. arctangent: the function the value of which for a given argument is the angle in radians the tangent of which is
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1-⑧: \displaystyle cot(\alpha-\beta)=\frac{cot\alpha·cot\beta+1}{cot\beta-cot\alpha} 五、倍角&半角公式 该部分内容可由公式直接推出。 1. 倍角公式 2-①:sin2α=2sinα·cosα (推理:将公式1-①中的β换成α) 2-②:cos2α=cos²α-sin²α (推理:将公式1-③中的β换成α) =...
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解:(1)由f(α)= \dfrac {\sin (α- \dfrac {π}{2})\cos ( \dfrac {3π}{2}+α)\tan (π-α)}{\tan (-\alpha -\pi )\sin (-\alpha -\pi )}= \dfrac {-\cos α\sin α\cdot (-\tan α)}{-\tan \alpha \cdot \sin \alpha }=-\cos α.(2)∵f(α)= \dfrac...
所以2\sin\alpha (2-\sin\alpha )=1-2\sin^2\alpha , 所以\sin\alpha ={1\over 4}, 因为\alpha \in (0,{\pi\over 2}), 所以\cos\alpha ={\sqrt{15}\over 4},\tan \alpha ={\sqrt{15}\over 15}。 故本题正确答案为A。 反馈 收藏 ...
解: 因为\cos \alpha =-\dfrac{3}{5},\alpha \in (0,\pi ), 所以\sin α= \sqrt{1-{\cos }^{2}α}= \dfrac{4}{5} , 所以\tan α= \dfrac{\sin α}{\cos α}= -\dfrac{4}{3}. 故选D.结果一 题目 已知是第二象限角,且,则( ) A.B. C.D. 答案 【答案...
解:(1)f(α)= \dfrac {\sin (π-α)\cos (2π-α)\sin (-α+ \dfrac {3π}{2})}{\tan (-\alpha -\pi )\sin (-\pi -\alpha )\cos (-\pi +\alpha )} = \dfrac {\sin α\cdot \cos α\cdot (-\cos α)}{-\tan \alpha \cdot \sin \alpha \cdot (-\cos \alpha ...
{4})=\frac{\tan \alpha +1}{1-\tan \alpha }=\frac{1}{7},解得\tan\alpha =-\frac{3}{4},又因为\alpha \in (\frac{\pi}{2},\pi),因此\left\{\eqalign{& \sin\alpha=\frac{3}{5}\cr& \cos \alpha =-\frac{4}{5} }\right.,因此\sin \alpha +\cos \alpha =-\...
设{\alpha}{\in}(0,\frac{{\pi}}{2}),{\beta}{\in}(0,\frac{{\pi}}{2}),且1 \frac{1}{{\tan}{\alpha}{\tan}{\beta}}=\frac{1}{{\sin}{\alpha}},则 A. 2{\beta}-{\alpha}=\frac{{\pi}}{2} B. 2{\beta}+{\alpha}=\frac{{\pi}}{2} C. 2{\alpha}...