""" 全纯函数判断 """ def is_holomorphic_function_1(expr,subs): #复变函数的复变量 free_z = expr.free_symbols new_subs = {} #将复变量的字典中,有用的拿出来 for k,v in subs.items(): if k in free_z: new_subs[k] = v #将复变量替换为(x+y*I) expr = expr.subs( new_subs...
'_from_list', '_from_poly', '_from_expr', '_from_domain_element', 'free_symbols', 'free_symbols_in_domain', 'gen', 'domain', 'zero', 'one', 'unit', 'is_zero', 'is_one', 'is_sqf', 'is_monic', 'is_
在Sympy 中表示常量符号,使其不是 free_symbol 应用程序我想创建一个 python 函数(例如Laplacian(expr))。expr拉普拉斯算子被定义为取关于每个变量的二阶偏导数之和(例如,Laplacian(f(x,y,z))isdiff(f,x,x) + diff(f,y,y) + diff(f,z,z)。在表达式中,可能有任意常量c,k等,就表达式而言,它们不是变量...
free_symbols = sympy.sympify(func).free_symbolsiflen(free_symbols) !=1orvariablenotinfree_symbols:raiseValueError("Cannot graph function of multiple variables")try: series = LineOver1DRangeSeries(func, (variable,-10,10), nb_of_points=200)# returns a list of [[x,y], [next_x, next_y]...
function,limits,free_symbols as_dummy 重命名虚拟变量 sympy.integrals.integrals.Integral.transform 对虚拟变量执行映射 property free_symbols 此方法返回对象中的符号,不包括那些取特定值的符号(即虚拟符号)。 示例 >>> from sympy import Sum >>> from sympy.abc import x, y >>> Sum(x, (x, y, 1...
free_symbols for _, sub in subst2), "Sub-expressions containing y must be ignored" assert any(sub - sqrt(x + 1) == 0 for _, sub in subst2), "cse failed to identify sqrt(x + 1) as sub-expression" 浏览完整代码 来源:test_cse.py 项目:asmeurer/sympy 示例9 def test_cse_not_...
free_symbols for a in solveset(f.subs(x, -0.139))) # issue 6632 assert nfloat(-100000*sqrt(2500000001) + 5000000001) == 9.99999999800000e-11 # issue 7122 eq = cos(3*x**4 + y)*rootof(x**5 + 3*x**3 + 1, 0) assert str(nfloat(eq, exponent=False, n=1)) == '-0.7*cos...
property free_symbols 多项式表达式的自由符号。 示例 >>> from sympy import Poly >>> from sympy.abc import x, y, z >>> Poly(x**2 + 1).free_symbols {x} >>> Poly(x**2 + y).free_symbols {x, y} >>> Poly(x**2 + y, x).free_symbols {x, y} >>> Poly(x**2 + y,...
assert all(i.free_symbols == sym for i in eqs) anx = solve(eq1, x)[0] yeq = eq2.subs(x, anx) z = unrad(yeq) z = z[0] if z else yeq yy = real_roots(z) def norm(x,y): return abs((x**2+y**2).n(2)) got=[] for yi in yy: yi = yi.n(n) ty = eqs.su...
free_symbols set([y]) is_number Return True if the Integral will result in a number, else False. Integrals are a special case since they contain symbols that can be replaced with numbers. Whether the integral can be done or not is another issue. But answering whether the final result ...