2.Smallest Subarray with a given sum(easy) 2.1 问题描述 2.2 解决方法 2.3 代码 3.课后回顾 4.参考链接 sliding window pattern 1.原理描述 滑动窗口模式(sliding window pattern)是用于在给定数组或链表的特定窗口大小上执行所需的操作,比如寻找包含所有 1 的最长子数组。
FindTabBarSize numsand an integerthe number of non-emptysubarrayswith a sumgoal. Asubarrayis a contiguous part of the array. Example 1: Input:nums = [1,0,1,0,1], goal = 2Output:4Explanation:The 4 subarrays are bolded and underlined below: [1,0,1,0,1] [1,0,1,0,1] [1,0,...
public int numSubarraysWithSum(int[] A, int S) { if (A.length == 0) return 0; int result = 0; int[] sumOne = new int[A.length]; int st = 0; int ed = 0; sumOne[0] = A[0] == 1 ? 1 : 0; for (int i = 1; i < A.length; i++) { sumOne[i] = A[i] =...
Shortest Subarray with Sum at Least K 参考资料: https://leetcode.com/problems/minimum-size-subarray-sum/ https://leetcode.com/problems/minimum-size-subarray-sum/discuss/59090/C%2B%2B-O(n)-and-O(nlogn) https://leetcode.com/problems/minimum-size-subarray-sum/discuss/59078/Accepted-clean-Ja...
第一种是prefix sum + 双指针。 例如Minimum Size Subarray Sum - LeetCode: Given an array of n positive integers and a positive integers, find the minimal length of a contiguous subarray of which the sum ≥s. If there isn't one, return 0 instead. 用O(N)时间得到一个prefix sum array,可...
题目地址:https://leetcode.com/problems/binary-subarrays-with-sum/description/题目描述In an array A of 0s and 1s, how many non-empty subarrays have sum S?Example 1:Input: A = [1,0,1,0,1], S = 2 Output: 4 Explanation: The 4 subarrays are bolded below: [1,0,1,0,1] [1,...
Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K.Example 1:Input: A = [4,5,0,-2,-3,1], K = 5Output: 7Explanation: There are 7 subarrays with a sum divisible by K = 5:[4, 5, 0, -2, -3, 1], [5]...
well, this problem aims to return the length of the shortest subarray of A with sum at least K. so let’s assume B is the accumulate array A. so which means we need to find the closest l~r which sum(A[l:r]) >= K, so => B[r] - K >= B[l], so if B[l] is fixed,...
这题跟560. subarray sum equals k几乎一毛一样。 我想到了用map和sum - k 来实现ONE PASS,但是不知道怎么维护一个类似560题里面那个count的值了。正确答案是用Math.max每次对比当前maxLen 和 i - map.get(sum-k)。 思维难度还是有的。 这题leetcode收费了。我贴一个别人的答案。注意这里的put始终是put...
In a given arraynumsof positive integers, find three non-overlapping subarrays with maximum sum. Each subarray will be of sizek, and we want to maximize the sum of all3*kentries. Return the result as a list of indices representing the starting position of each interval (0-indexed). If ...