Say you have an array for which theith element is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. 思路:变相的求最大子数组,是算法导论上...
Say you have an array for which theithelement is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. 思路:这道题就是让自己能得到最大的利润...
package day_40;// 个人感觉这个题目和 之前的Stock2是一样的// 上面那句是错的,实际上两个题目是不同的思路。publicclassBuySellStock3{publicintmaxProfit(int[]prices){int[]local=newint[3];// k+1int[]global=newint[3];for(inti=1;i<prices.length;i++){intdiff=prices[i]-prices[i-1];for...
classSolution:defmaxProfit(self,prices:List[int])->int:## 双指针解法left,right=0,1# left=buy, right=sellmaxP=0whileright<len(prices):## 遍历整个 listifprices[right]>prices[left]:## 在存在赚钱机会的条件下profit=prices[right]-prices[left]maxP=max(maxP,profit)else:## 对于任意一个右指...
9 8 7 3 2 但是对于我们的代码,持续下跌的话,buy 和 sell - 1 就相等了,所以每次累计就是 0,不影响结果 解法二 其实不用考虑那么多,再直接点,只要当前天相对于前一天上涨了,我们就前一天买入,当前天卖出。 public int maxProfit(int[] prices) { int profit = 0; for (int i = 1; i < prices....
Buy1[i]=max{Buy[i-1],-prices[i]} 可以发现上面四个状态都是只与前一个状态有关,所以可以不使用数组而是使用变量来存储即可。 class Solution { public: int maxProfit(vector<int> &prices) { if(prices.size()<2)return 0; int buy1=INT_MIN,sell1=0,buy2=INT_MIN,sell2=0; ...
If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. class Solution { public: //只做一次交易 寻找最大的差值即可 int maxProfit(vector<int>& prices) { ...
Can you buy and sell stock on the same day? This is known as day trading, and in this guide, we'll walk you through it and set you up for success.
In order to rate stocks as buy, sell, or hold, analysts research public financial statements, listen in on conference calls, and talk to managers and the customers of a company.
Here are some ideas to help you identify the right time to either buy or sell a stock for your portfolio.