由此,我们从第1天(下标为0)开始,画出全部的状态转换图,如下: 该图中,每一条从0到n的路径表示一种可能的交易方式,则该状态转换图包含了全部可能的交易方式。这就是解空间,有了它我们才能想办法在其中求一个最大值,接下来就是动态规划的内容了。 二,动态规划 上一段中的状态好理解,但是在程序中如何表示和...
其实这里还有一种思路,就是贪心法,只要当天的价格高于前一天的,就算入收益。 intmaxProfit=0;for(inti=1;i<prices.length;i++){if(prices[i]>prices[i-1])maxProfit+=prices[i]-prices[i-1];}returnmaxProfit; 3. BestTimetoBuyandSellStock 3 这里限制最多只能进行2次交易。 第一次我的想法就是,这个...
121. Best Time to Buy and Sell Stock 122. Best Time to Buy and Sell Stock II 123. Best Time to Buy and Sell Stock III 188. Best Time to Buy and Sell Stock IV 309. Best Time to Buy and Sell Stock with Cooldown 714. Best Time to Buy and Sell Stock with Transaction Fee 以上每个...
然后sell往后移, 若prices[sell] < prices[buy],则将buy指向sell当前位置(buy = sell),否则计算当前股票买卖收益,并和之前计算的收益比较,取最大的值。 1//双指针法求股票买卖最佳时机问题23intmaxProfit_doublePtr(vector<int>&prices)4{5intbuy=0,sell=0;6intmaxProfit =0;7for(;sell<prices.size();++...
找第j天prices[buy] - dp[buy][k - 1]的最小值的时候,我们考虑了prices[0] - dp[0][k - 1]、prices[1] - dp[1][k - 1]、prices[2] - dp[2][k - 1]...,找第j + 1天prices[buy] - dp[buy][k - 1]的最小值的时候,我们又会从头考虑prices[0] - dp[0][k - 1]、prices[...
LeetCode121. Best Time to Buy and Sell Stock JonesM https://leetcode.com/problems/best-time-to-buy-and-sell-stock/leetcode.com/problems/best-time-to-buy-and-sell-stock/ 解题思路 1. 暴力 O(n2) 复杂度,超时 class Solution { public: int maxProfit(vector<int>& prices) { int maxVal...
给定一个数组prices,它的第i个元素prices[i]表示一支给定股票第i天的价格。 你只能选择某一天买入这只股票,并选择在未来的某一个不同的日子卖出该股票。设计一个算法来计算你所能获取的最大利润。 返回你可以从这笔交易中获取的最大利润。如果你不能获取任何利润,返回0。
Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may not engage in multiple transactions at the same time (ie, you must sell the stock before...
0121. Best Time to Buy and Sell Stock (E)Best Time to Buy and Sell Stock (E) 题目 Say you have an array for which the (i^{th}) element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (i.e., buy one and sell one ...
public class BestTimetoBuyandSellStock { [TestMethod] public void MaxProfit() { int[] price = new[] { 2,3,2,5 }; var temp = Algorithm.Model.BestTimetoBuyandSellStock.MaxProfit(price); Assert.AreEqual(temp, 3); price = new[] ...