Runtime: 44 ms, faster than 67.87% of Python3 online submissions for Best Time to Buy and Sell Stock II. Memory Usage: 13.8 MB, less than 5.06% of Python3 online submissions for Best Time to Buy and Sell Stock II. 改进版本1: 这个结果还是比较满意的,但是仍有优化的空间,首先是判断if太多...
9 8 7 3 2 但是对于我们的代码,持续下跌的话,buy 和 sell - 1 就相等了,所以每次累计就是 0,不影响结果 解法二 其实不用考虑那么多,再直接点,只要当前天相对于前一天上涨了,我们就前一天买入,当前天卖出。 public int maxProfit(int[] prices) { int profit = 0; for (int i = 1; i < prices....
同样不需要额外的空间,而且只需要O(n)的空间复杂度。思路就是我一开始没有钱,buy1是我第一次买股票之后剩的钱(肯定是负的,我白手起家,借钱买股票啊),sell1是我卖完第一次买的股票之后剩的钱(>=0),buy2是我用上回挣得钱(有可能需要找别人再借一点)买第二次股票,sell2是我卖完第二次股票之后剩下的钱。
01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第32题(顺位题号是122)。假设有一个数组,其中第i个元素是第i天给定股票的价格。设计算法以找到最大利润。可以根据需要完成尽可能多的交易(即,多次买入并卖出一股股票)。 注意:不能同时进行多笔交易(即,您必须在再次购买之前卖出股票)。 例如: 输入:[7,...
You can only hold at most one share of the stock at any time. However, you can buy it then immediately sell it on the same day. Find and return the maximum profit you can achieve. 给定一个整数数组 prices,其中 prices[i] 表示第 i 天的股票价格。 每天,你可以选择买入和/或卖出股票。你...
Best Time to Buy and Sell Stock IV中是求某个给定k次交易的最大收益,和Maximum Subarray III完全一样 本题由于是可以操作任意次数,只为获得最大收益,而且对于一个上升子序列,比如:[5, 1, 2, 3, 4]中的1, 2, 3, 4序列来说,对于两种操作方案: 1 在1买入,4卖出 2 在1买入,2卖出同时买入,3卖出...
Best Time to Buy and Sell Stock II Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times)...
Best Time to Buy and Sell Stock 买卖 Best Time to Buy and Sell Stock Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design ...
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