When you split a stringsintosprefixandssuffix, eitherssuffixorsprefixis allowed to be empty. For example, ifs = "abc", then"" + "abc","a" + "bc","ab" + "c", and"abc" + ""are valid splits. Returntrueif it is possible to forma palindrome string, otherwise returnfalse. Notice ...
splitting a into two strings: aprefix and asuffix where a = aprefix + asuffix, and splitting b into two strings: bprefix and bsuffix where b = bprefix + bsuffix. Check if aprefix + bsuffix or bprefix + asuffix forms a palindrome. ...
// LeetCode 2020 medium #800// 1616. Split Two Strings to Make Palindrome// https://leetcode.com/problems/split-two-strings-to-make-palindrome/// Runtime: 76 ms, faster than 94.71% of C++ online submissions for Split Two Strings to Make Palindrome.// Memory Usage: 24.5 MB, less than...
Simple, free, and easy to use online tool that splits strings. Just load your string here and it'll get split into pieces.
public: bool checkPalindromeFormation(string a, string b) { int left = a.size() / 2 - 1; left = min(check(a, a, left), check(b, b, left)); left = min(check(a, b, left), check(b, a, left)); return left == -1; ...
classSolution{ public: boolcheckPalindromeFormation(stringa,stringb) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 a = "x" b = "y" 9 1 2 3 4 5 6 › "x" "y" "xbdef" "xecab" "ulacfd" "jizalu" Source...
1616. 分割两个字符串得到回文串 - 给你两个字符串 a 和 b ,它们长度相同。请你选择一个下标,将两个字符串都在 相同的下标 分割开。由 a 可以得到两个字符串: aprefix 和 asuffix ,满足 a = aprefix + asuffix ,同理,由 b 可以得到两个字符串 bprefix 和 bsuffix ,满