这时候就需要想到前缀和。 classSolution{public:vector<bool>canMakePaliQueries(string s, vector<vector<int>>& queries){intsz = s.size(); vector<vector<int>>cnts(sz+1); cnts[0] =vector<int>(26,0);for(inti =0; i < sz; ++i) { cnts[i+1] = cnts[i]; cnts[i+1][s[i] -'a'...
1#define_for(i,a,b) for(int i = (a);i < b;i ++)2#define_rep(i,a,b) for(int i = (a);i > b;i --)34classSolution5{6public:7vector<bool> canMakePaliQueries(strings, vector<vector<int>>&queries)8{9vector<bool>v;10longlongsum[100003][27];11memset(sum,0,sizeof(sum))...
If the substring is possible to be a palindrome string after the operations above, the result of the query istrue. Otherwise, the result isfalse. Return an arrayanswer[], whereanswer[i]is the result of thei-th queryqueries[i]. Note that: Each letter is counted individually for replacement...
standard output A string is called palindrome if it reads the same from left to right and from right to left. For example "kazak", "oo", "r" and "mikhailrubinchikkihcniburliahkim" are palindroms, but strings "abb" and "ij" are not. You are given stringsconsisting of lowercase Latin...
Hello everyone. Recently I saw an interesting problem and could not solve it. I think you can help :) Given a stringss. In one operation, you can delete a character or swap adjacent characters. Find minimum number of operations to make a string palindrome. ...
A string is called palindrome if it reads the same from left to right and from right to left. For example "kazak", "oo", "r" and "mikhailrubinchikkihcniburliahkim" are palindroms, but strings "abb" and "ij" are not. You are given stringsconsisting of lowercase Latin letters. At ...
1309-Decrypt-String-from-Alphabet-to-Integer-Mapping 1310-XOR-Queries-of-a-Subarray 1311-Get-Watched-Videos-by-Your-Friends 1312-Minimum-Insertion-Steps-to-Make-a-String-Palindrome 1317-Convert-Integer-to-the-Sum-of-Two-No-Zero-Integers 1318-Minimum-Flips-to-Make-a-OR-b-Equal-to-c 1319-Nu...
Count Palindrome Sub-Strings of a String - GFG Count number of hops - GFG Count pairs in array divisible by K - GFG Count the elements - GFG Count ways to express N as the sum of 1,3 and 4 - GFG Count ways to reach the n'th stair - GFG DFS of Graph - GFG...
You just need to check if any word is a palindrome (if str1 == str1[::-1]). Simpler code comes from simpler algorithns. I don't think your code is overly long for what you were trying to do 😉 31st Oct 2020, 10:00 AM Russ + 5 Yes! Coding is so much about working out ...
Java_com_example_myapplication_MainActivity_stringFromJNI( JNIEnv* env, jobject /* this */) { std::string hello = "Hello"; std::string world = " World!"; return env->NewStringUTF((hello + world).c_str()); } The file named "CMakeList.txt" is being referred to. ...