1. Find minimum in rotated sorted array(https://oj.leetcode.com/problems/find-minimum-in-rotated-sorted-array/) 解题思路: L为array左端,R为array右端,M = (L+R)/2,若num[M] > num[R], 则说明rotated的部分在右边,最小值为M+1 ~ R中的一个元素。若num[M] < num[R], 则说明rotated...
LeetCode上牵扯到Rotated Sorted Array问题一共有四题,主要是求旋转数组的固定值或者最小值,都是考察二分查找的相关知识。在做二分查找有关的题目时,需要特别注重边界条件和跳出条件。在做题的过程中,不妨多设几个测试案例,自己判断一下。 下面是这四题的具体解答。 33.Search in Rotated Sorted Array 在求旋转...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array...
There is an integer array nums sorted in ascending order (with distinct values). 一个升序排序的整数数组 Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1 <= k < nums.length) such that the resulting array is [nums[k], nums[k+1], ......
My code: My test result: 这不是一个好方法。下面介绍 binary search 版方法。 My code: My test result: 一下子快...
Given the sorted rotated arraynumsofuniqueelements, returnthe minimum element of this array. You must write an algorithm that runs inO(log n) time. Example 1: Input: nums = [3,4,5,1,2] Output: 1 Explanation: The original array was [1,2,3,4,5] rotated 3 times. ...
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. ...
[Leetcode 33/81]有序旋转数组找值Search in Rotated Sorted Array,leetcode33【题目】顺序排列的数组,每个点值不同。以某个点进行旋转(其实就是前后两段交换位置),对旋转后数组搜索有无target,没有-1,有返回位置(变式81不同点在于会出现重复数字)Thereisanintegerar
题目描述 题目描述 题解 提交记录 提交记录 代码 测试用例 测试结果 测试结果 全部题解 题解不存在 请查看其他题解 C++ 智能模式 1 2 3 4 5 6 class Solution { public: int search(vector<int>& nums, int target) { } }; 已存储 行1,列 1 运行和提交代码需要登录 Case 1Case 2Case 3 nums...
但是这道题,由于数组「被旋转」,所以左侧或者右侧区间不一定是连续的。在这种情况下,如何判断 target 位于哪个区间?根据旋转数组的特性,当元素不重复时,如果 nums[i] <= nums[j],说明区间 [i,j] 是「连续递增」的。i、j 可以重合,所以这里使用的比较运算符是「小于等于」 因此,在旋转排序数组中查找一个特定...