1. Find minimum in rotated sorted array(https://oj.leetcode.com/problems/find-minimum-in-rotated-sorted-array/) 解题思路: L为array左端,R为array右端,M = (L+R)/2,若num[M] > num[R], 则说明rotated的部分在右边,最小值为M+1 ~ R中的一个元素。若num[M] < num[R], 则说明rotated...
FindHeaderBarSize There is an integer arraynumssorted in ascending order (withdistinctvalues). Prior to being passed to your function,numsispossibly rotatedat an unknown pivot indexk(1 <= k < nums.length) such that the resulting array is[nums[k], nums[k+1], ..., nums[n-1], nums[...
LeetCode上牵扯到Rotated Sorted Array问题一共有四题,主要是求旋转数组的固定值或者最小值,都是考察二分查找的相关知识。在做二分查找有关的题目时,需要特别注重边界条件和跳出条件。在做题的过程中,不妨多设几个测试案例,自己判断一下。 下面是这四题的具体解答。 33.Search in Rotated Sorted Array 在求旋转...
Can you solve this real interview question? Search in Rotated Sorted Array - There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1
Search in Rotated Sorted Array I && II Leetcode 对有序数组进行二分查找(下面仅以非递减数组为例): 1. int binarySort(int A[], int lo, int hi, int target) 2. { 3. while(lo <= hi) 4. { 5. int mid = lo + (hi - lo)/2; ...
题目链接:https://leetcode.com/problems/search-in-rotated-sorted-array/题目: Suppose a sorted array is rotated at some pivot unknown to you beforehand. 0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, ...
Output: 0 Note: This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。
[ 4 5 6 7 1 2 3] ,如果 target = 2,那么数组可以看做 [ -inf -inf - inf -inf 1 2 3]。 和解法一一样,我们每次只关心 mid 的值,所以 mid 要么就是 nums [ mid ],要么就是 inf 或者 -inf。 什么时候是 nums [ mid ] 呢?
nums is an ascending array that is possibly rotated. -104 <= target <= 104 思考 从题目提及的时间复杂度,可以知道这次肯定是需要用到二分法的。 我们先分析一下旋转之后(r1,r2)->(r2,r1)的列表。 [4,5,6,7,0,1,2] 这样一个列表,我们可以知道,因为是将升序列表的r2部分移植到了r1部分,所以移植...
LeetCode-33-搜索旋转排序数组(Search in Rotated Sorted Array)33. 搜索旋转排序数组整数数组 nums 按升序排列,数组中的值 互不相同。在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转,使数组变为 [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1...