如果我们不用这种方法,那么我们需要更加深入地去判断每种可能出现地情况。 当nums[mid] > nums[start] 和 nums[mid] < nums[end] 都不满足时,则: numd[start] <= nums[mid] 并且 nums[mid] >= nums[end] 如果我们再仔细想,由于数组旋转之前整体有序,那么旋转之后得到的两条线段本身应该是有序的,而且...
此题是Search in Rotated Sorted Array的加强版,将一个有序数组往右移动若干位。这里的有序数组允许有重复数字。 如果没有重复数字,那么复杂度是O(logn),用二分查找,根据中间值和左右两边的大小,以及和target的大小,来判断缩小一半查找。 但是出现重复数字之后,如果中间值和左右两边的值相等,我们就不知道如何切除...
Can you solve this real interview question? Search in Rotated Sorted Array II - There is an integer array nums sorted in non-decreasing order (not necessarily with distinct values). Before being passed to your function, nums is rotated at an unknown piv
FindHeaderBarSize There is an integer arraynumssorted in ascending order (withdistinctvalues). Prior to being passed to your function,numsispossibly rotatedat an unknown pivot indexk(1 <= k < nums.length) such that the resulting array is[nums[k], nums[k+1], ..., nums[n-1], nums[...
题目链接:https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ 题目: Follow up for “Search in Rotated Sorted Array”: What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. ...
This is a follow up problem to Search in Rotated Sorted Array, where nums may contain duplicates. Would this affect the run-time complexity? How and why? 分析 题目的意思是:给你一个旋转的有序数组,数组中是否存在一个数等于给定的target。
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今天的笔记包含基于改造二分法(Modified Binary Search)类型下的7个题目,它们在leetcode上的编号和题名分别是: 704 - 二分查找 74 - 搜索二维矩阵 33 - 搜索旋转排序数组 81 - 搜索旋转排序数组 II 153 - 寻找旋转排序数组中的最小值 162 - 寻找峰值 ...
LeetCode-33-搜索旋转排序数组(Search in Rotated Sorted Array)33. 搜索旋转排序数组整数数组 nums 按升序排列,数组中的值 互不相同。在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转,使数组变为 [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1...