此题是Search in Rotated Sorted Array的加强版,将一个有序数组往右移动若干位。这里的有序数组允许有重复数字。 如果没有重复数字,那么复杂度是O(logn),用二分查找,根据中间值和左右两边的大小,以及和target的大小,来判断缩小一半查找。 但是出现重复数字之后,如果中间值和左右两边的值相等,我们就不知道如何切
如果我们不用这种方法,那么我们需要更加深入地去判断每种可能出现地情况。 当nums[mid] > nums[start] 和 nums[mid] < nums[end] 都不满足时,则: numd[start] <= nums[mid] 并且 nums[mid] >= nums[end] 如果我们再仔细想,由于数组旋转之前整体有序,那么旋转之后得到的两条线段本身应该是有序的,而且...
You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. 就是在一个旋转后的数组中寻找target数据。 很明显,最简单的方法就是遍历一次,不过题目的意思明显不是要求这么做的,主要考察的还是使用二分查找,...
[leetcode] 81. Search in Rotated Sorted Array II Description Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,0,1,2,2,5,6] might become [2,5,6,0,0,1,2]). You are given a target value to search. If found in the ar...
Example 1: Input: nums = [2,5,6,0,0,1,2], target = 0 Output: true Example 2: Input: nums = [2,5,6,0,0,1,2], target = 3 Output: false Noted that: The array may contain dumplicated value, so this is different to Leet Code 33. Search in Rotated Sorted Array In the ...
Can you solve this real interview question? Search in Rotated Sorted Array - There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1
Can you solve this real interview question? Search in Rotated Sorted Array - There is an integer array nums sorted in ascending order (with distinct values). Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1
Search in Rotated Sorted Array(c语言版本) bingo酱 I am a fighter 来自专栏 · leetcode每日斩 题目大意: 给定一个旋转升序的数组,所谓旋转就是假设把头和尾连接起来,然后找到最小那个数开始,往后开始就是升序的,直到再回到最小那个数为止。这样看起来就像一个环一样。 然后,现在给定一个数,要从这个数组...
小范的leetcode日记(33)Search in Rotated Sorted Array, 视频播放量 16、弹幕量 0、点赞数 1、投硬币枚数 0、收藏人数 1、转发人数 0, 视频作者 小范刷题, 作者简介 ,相关视频:小范的leetcode日记(81)Search in Rotated Sorted Array II,小范的leetcode日记(80)Remove D
LeetCode-33-搜索旋转排序数组(Search in Rotated Sorted Array)33. 搜索旋转排序数组整数数组 nums 按升序排列,数组中的值 互不相同。在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转,使数组变为 [nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1...