You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. 题解: 这道题是一道常见的二分查找法的变体题。 要解决这道题,需要明确rotated sorted array的特性,那么就是至少有一侧是排好序的(无论pivot...
}privateintsearch(int[] nums,intlow,inthigh,inttarget) {if(low >high)return-1;intmid = (low + high) / 2;if(nums[mid] ==target)returnmid;if(nums[mid] <nums[high]) { //后半部分有序if(nums[mid] < target && target <=nums[high]) //在有序部分,则继续二分此部分returnsearch(num...
Search in Rotated Sorted Array I && II Leetcode 对有序数组进行二分查找(下面仅以非递减数组为例): 1. int binarySort(int A[], int lo, int hi, int target) 2. { 3. while(lo <= hi) 4. { 5. int mid = lo + (hi - lo)/2; 6. if(A[mid] == target) 7. return mid; 8....
There is an integer arraynumssorted in ascending order (with distinct values). Prior to being passed to your function,numsis rotated at an unknown pivot indexk(0 <= k < nums.length) such that the resulting array is[nums[k], nums[k+1], ..., nums[n-1], nums[0], nums[1], .....
leetCode 33. Search in Rotated Sorted Array(c语言版本) bingo酱 I am a fighter 来自专栏 · leetcode每日斩 题目大意: 给定一个旋转升序的数组,所谓旋转就是假设把头和尾连接起来,然后找到最小那个数开始,往后开始就是升序的,直到再回到最小那个数为止。这样看起来就像一个环一样。 然后,现在给定一个数,...
33. Search in Rotated Sorted Array 寻找旋转排序数组 There is an integer array nums sorted in ascending order (with distinct values). 一个升序排序的整数数组 Prior to being passed to your function, nums is possibly rotated at an unknown pivot index k (1 <= k < nums.length) such that th...
题目 33. Search in Rotated Sorted Array 题解 题目意思就是在一个上升序列中截断成AB 两个子序列 然后BA拼接成一个新的序列, 而题目要求 我们查找在这个序列中是否存在target,如果看到这里就会发现 这个很简单啊,查找一个序列中是否有某个数字 直接遍历就好了 方法木佬佬,但是 最重要的是题目末尾有一句 ...
(i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. 原问题链接:https://leetcode.com/problems/search-in-rotated-sorted-array/...
2019-11-24 12:03 −原题链接在这里:https://leetcode.com/problems/search-in-a-sorted-array-of-unknown-size/ 题目: Given an integer array sorted in ascending order, write a fun... Dylan_Java_NYC 0 1310 [LC] 81. Search in Rotated Sorted Array II ...
Java public int binarySearchRight(int[] nums, int target) { // 搜索区间为 [left, right] int left = 0 int right = nums.length - 1; while (left <= right) { int mid = left + (right - left) / 2; if (nums[mid] < target) { // 搜索区间变为 [mid+1, right] left = mid +...