Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. SOLUTION 1: 这个题目trick的地方在于,它的旋转pivot次数未知。所以有可能它转...
我们须要分情况处理。当然也能够无论这些直接遍历,即从头到尾扫描,找出最小的数;假设依据题意,我们须要考虑 1、 当严格单调时,因为是排好序的所以我们直接return 第一个元素就可以;或者直接利用二分法查找也能够。 2、 当有拐点时,我们就能够二分查找高速找到最小值。 综上所诉。考虑两种情况能够提高效率,可是直...
Find the minimum element. You may assume no duplicate exists in the array. 本题难度Medium。 二分查找法 【复杂度】 时间O(N) 空间 O(N) 【思路】 题目假设:You may assume no duplicate exists in the array. 这道题与其他Rotated Sorted Array题一样可以用改良的二分查找法来做。 原则是只要一直...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 数列基本有序,则使用二分查找。假设数列是n,s是起始下标,e是最后下标,m是中...
【摘要】 Leetcode 题目解析之 Find Minimum in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element.
Leetcode Find Minimum in Rotated Sorted Array 题目大意: 对一个有序数组翻转, 就是随机取前K个数,移动到数组的后面,然后让你找出最小的那个数,注意,K有可能是0,也就是没有翻转。 毫无疑问,遍历一次肯定可以找到,但这样时间复杂度是O(n),如果你在面试的时候遇到这样的问题,你这样回答面试官肯定不会满意的...
题目链接:https://leetcode-cn.com/problems/find-minimum-in-rotated-sorted-array-ii/ 一、题目描述 把一个数组最开始的若干个元素搬到数组的末尾,我们称之为数组的旋转。输入一个递增排序的数组的一个旋转,输出旋转数组的最小元素。例如,数组 [3,4,5,1,2] 为 [1,2,3,4,5] 的一个旋转,该数组的最...
My code: My test result: 这不是一个好方法。下面介绍 binary search 版方法。 My code: My test result: 一下子快...
Description Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. ...
Given the sorted rotated arraynumsofuniqueelements, returnthe minimum element of this array. You must write an algorithm that runs inO(log n) time. Example 1: Input: nums = [3,4,5,1,2] Output: 1 Explanation: The original array was [1,2,3,4,5] rotated 3 times. ...