Given an array nums, return true if the array was originally sorted in non-decreasing order, then rotated some number of positions (including zero). Otherwise, return false. There may be duplicates in the origi
LeetCode上牵扯到Rotated Sorted Array问题一共有四题,主要是求旋转数组的固定值或者最小值,都是考察二分查找的相关知识。在做二分查找有关的题目时,需要特别注重边界条件和跳出条件。在做题的过程中,不妨多设几个测试案例,自己判断一下。 下面是这四题的具体解答。 33.Search in Rotated Sorted Array 在求旋转...
1. Find minimum in rotated sorted array(https://oj.leetcode.com/problems/find-minimum-in-rotated-sorted-array/) 解题思路: L为array左端,R为array右端,M = (L+R)/2,若num[M] > num[R], 则说明rotated的部分在右边,最小值为M+1 ~ R中的一个元素。若num[M] < num[R], 则说明rotated...
Search in Rotated Sorted Array I && II Leetcode 对有序数组进行二分查找(下面仅以非递减数组为例): 1. int binarySort(int A[], int lo, int hi, int target) 2. { 3. while(lo <= hi) 4. { 5. int mid = lo + (hi - lo)/2; 6. if(A[mid] == target) 7. return mid; 8....
You may assume no duplicate exists in the array. 本题难度hard。利用二分查找法即可。分别使用迭代和递归实现。 【题意】 题目的意思是对rotated后的array,利用它的局部有序性来找到target,返回其index。 【思路】 首先要明白二分查找法快在哪里。二分查找法是通过判断下中点和目标的关系,就可以知道目标在左...
Search in Rotated Sorted Array(c语言版本) bingo酱 I am a fighter 来自专栏 · leetcode每日斩 题目大意: 给定一个旋转升序的数组,所谓旋转就是假设把头和尾连接起来,然后找到最小那个数开始,往后开始就是升序的,直到再回到最小那个数为止。这样看起来就像一个环一样。 然后,现在给定一个数,要从这个数组...
Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。
小范的leetcode日记(33)Search in Rotated Sorted Array, 视频播放量 16、弹幕量 0、点赞数 1、投硬币枚数 0、收藏人数 1、转发人数 0, 视频作者 小范刷题, 作者简介 ,相关视频:小范的leetcode日记(81)Search in Rotated Sorted Array II,小范的leetcode日记(80)Remove D
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. ...