4.重复步骤1~3,直到排序完成。动图演示代码实现 C++vector<int> bubbleSort(vector<int>& arr) { int len = arr.size(); for (int i = 0; i < len - 1; i++) { for (int j = 0; j < len - 1 - i; j++) { if (arr[j] > arr[j + 1]) { // 相邻元素两两对比 int temp ...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
1.Bubble sort, 可以理解为每一次找最大的值放在最后面,然后再找第二个最大的值放在倒数第二个位置上,以此类推。 T: O(n ^ 2) ; S: O(1) defbubbleSort(self, nums): n=len(nums)foriinrange(n - 1, 0, -1):#from n - 1 to 1, because j starts from 0swapped =Falseforjinrange(0,...
This method takes two sorted arrays (left and right) and merges them into a single sorted array. Initialization: An empty listsorted_arrayis created to store the merged result. Two pointersiandjare initialized to 0, pointing to the current elements of the left and right arrays, respectively. ...
Given an array with n objects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue. Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively. void sort...
name } return names } type People struct { name string height int } 题目链接: Sort the People: leetcode.com/problems/s 按身高排序: leetcode.cn/problems/so LeetCode 日更第 267 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满 发布于 2022-10-15 10:04...
Output: [2,3,4,1] Explanation: First, we sort the values present at odd indices (1 and 3) in non-increasing order. So, nums changes from [4,1,2,3] to [4,3,2,1]. Next, we sort the values present at even indices (0 and 2) in non-decreasing order. So, nums changes from...
力扣LeetCode中文版,码不停题 -全球极客编程职业成长社区 🎁 每日任务|力扣 App|百万题解|企业题库|全球周赛|轻松同步,使用已有积分换礼 × Problem List Problem List RegisterorSign in Premium Medium Topics Companies Given theheadof a singly linked list, sort the list usinginsertion sort, and return...
int[] res; public int[] searchRange(int[] nums, int target) { res = new int[]{-1, -1}; help(nums, target, 0, nums.length-1); return res; } public void help(int[] nums, int target, int s, int e){ if(s > e) return; int mid = (s+e) / 2; if(nums[mid] == ...
Input:head = [-1,5,3,4,0] Output:[-1,0,3,4,5] Constraints: The number of nodes in the list is in the range [1, 5000]. -5000 <= Node.val <= 5000 From: LeetCode Link:147. Insertion Sort List Solution: Ideas: 1. Node Definition and Creation: ...