A rather straight forward solution is a two-pass algorithm using counting sort. First, iterate the array counting number of 0's, 1's, and 2's, then overwrite array with total number of 0's, then 1's and followed by 2's. Could you come up with an one-pass algorithm using only co...
https://oj.leetcode.com/discuss/3577/i-use-quick-sort-to-sort-the-list-but-why-i-get-time-limited View Code GITHUB: https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/list/SortList.java
Here, we will use the integers 0, 1, and 2 to represent the color red, white, and blue respectively. Note: You are not suppose to use the library’s sort function for this problem. Example: Input: [2,0,2,1,1,0] Output: [0,0,1,1,2,2] 2. 分析思路1 通过第一次遍历记录0、...
LeetCode--350. Intersection of Two Arrays II(两个数组的交集)Python 题目: 给定两个数组,返回这两个数组的交集。 解题思路: 使用哈希表用来存储第一个数组中的内容。再遍历第二个数组,看该数组的数字是否在哈希表中,在则将该数字加入输出的列表中。 代码(Python):......
publicclassSort{publicstaticvoidmain(String[]args){int[]unsortedArray=newint[]{6,5,3,1,8,7,2,4};bubbleSort(unsortedArray);System.out.println("After sort: ");for(intitem:unsortedArray){System.out.print(item+" ");}}publicstaticvoidbubbleSort(int[]nums){intlen=nums.length;for(inti=0;...
1classSolution {2publicString frequencySort(String s) {3HashMap<Character, Integer> map =newHashMap<>();4for(charc : s.toCharArray()) {5map.put(c, map.getOrDefault(c, 0) + 1);6}78List<Character>[] bucket =newList[s.length() + 1];9for(charkey : map.keySet()) {10intfreq...
//compare参数实现,匿名函数lambda,这种比较方法的可行性ASCII码的比较,0对应dec的48 in ASCII中美国标准信息交换代码ANSI制定 string res; for(auto s:arr) res+=s; while(res[0]=='0' && res.length()>1) res.erase(0,1); /*erase函数的原型如下: ...
遍历一遍的方法:https://leetcode.com/discuss/17000/share-my-one-pass-constant-space-10-line-solution the idea is to sweep all 0s to the left and all 2s to the right, then all 1s are left in the middle. classSolution {public:voidsortColors(intA[],intn) {intsecond=n-1, zero=0;f...
https://leetcode.com/problems/sort-colors/#/description Given an array withnobjects colored red, white or blue, sort them so that objects of the same color are adjacent, with the colors in the order red, white and blue. Here, we will use the integers 0, 1, and 2 to represent the ...