zero =0;56for(inti =0; i < n; ++i) {7if(A[i] ==2) {8A[two++] =2;9}elseif(A[i] ==1) {10A[two++] =2;11A[one++] =1;12}else{13A[two++] =2;14A[one++] =1;15A[zero++] =0;16}17}18}19};
Base Case: If the array has one or zero elements, it is already sorted, so the function returns the array as is. Divide: The array is divided into two halves using the middle index. Recursion: The merge_sort method is called recursively on the left half and the right half of the arra...
代码如下: 1classSolution {2public:3voidsortColors(intA[],intn) {4if(n ==0)5return;6intzero =0,two = n-1;7for(inti =0;i <=two;){8if(A[i] ==0){9swap(A[i],A[zero]);10zero++;11i++;12}13elseif(A[i] ==1)14i++;15elseif(A[i] ==2){16swap(A[i],A[two]);...
结合三路快排partition思路的应用,设定两个索引,一个从左往右滑动zero,一个从右往左滑动two,遍历nums,当nums[i]的值为1时,i++;当nums[i]的值为2时,two的值先减1,而后交换nums[i]与nums[two],此时在观察nums[i]的值;当nums[i]的值为0时,zero++,而后交换nums[i]与nums[zero],i++;当 i = two时...
intlastzero =0, firsttwo = nums.length-1; for(inti =0; i <= firsttwo; i++) { if(nums[i] ==0) swap(nums,i,lastzero++); elseif(nums[i] ==2) **swap(nums,i--,firsttwo--);** } } publicvoidswap(int[] nums,inti,intj){ ...
swap(nums[++zero],nums[i++]); else if(nums[i] == 2) swap(nums[--two],nums[i]); } } }; 另一种写法: /* 由于只有012 三个数为此选择1作为基准v 而通用的基准往往是放在第一个位置,并从第二个位置开始,所以结束后最后还要将基准v放到合适的位置 ...
1203. Sort Items by Groups Respecting Dependencies # 题目 # There are n items each belonging to zero or one of m groups where group[i] is the group that the i-th item belongs to and it’s equal to -1 if the i-th item belongs to no group. The items and
参考代码 packageleetcodefuncsortColors(nums[]int){zero,one:=0,0fori,n:=rangenums{nums[i]=2ifn<=1{nums[one]=1one++}ifn==0{nums[zero]=0zero++}}} 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16.
排序算法radixSort原理:我们先在CPU上实验下:(因为GPU上实在是太不容易发现问题了,在Cpu上把大致框架搞出来再搬过去~) 对于一个随机的两位Int的数组排序:(详细可以参考别的资料,如LeetCode的排序算法和算…
🎭 PsuendoCode 📐 Matrix Pattern 📐 ⏰: O(n^3) 🪐: O(n^2) int n = matrix.length; for (i = 0; i < n; i++) { if (matrix[i][i] == 0) { boolean zeroRow = true; for (j = 0; j < n; j++) { if (matrix[i][j] != 0) { zeroRow = false; break; }...