百度试题 结果1 题目sinxcosxcos2x求详细解答 相关知识点: 试题来源: 解析 sinxcosxcos2x=(1/2)sin2xcos2x=(1/2)×(1/2)sin4x=(1/4)sin4x 反馈 收藏
解析 解:sinxcosxcos2x =1/2sin2x⋅cos2x =1/4sin4x结果一 题目 sinxcosxcos2x(化简)详细点哦! 答案 sinxcosxcos2x=1/2×(2sinxcosx)cos2x=1/2sin2xcos2x 二倍角公式=1/4(2sin2xcos2x)=(sin4x)/4相关推荐 1sinxcosxcos2x(化简)详细点哦!
答案解析 查看更多优质解析 解答一 举报 sinxcosxcos2x=1/2×(2sinxcosx)cos2x=1/2sin2xcos2x 二倍角公式=1/4(2sin2xcos2x)=(sin4x)/4 解析看不懂?免费查看同类题视频解析查看解答 更多答案(1) 相似问题 化简①(sinα+cosα)2②cos^4θ-sin^4θ③sinxcosxcos2x④[1/(1-tanθ)]-[1/1+tan...
=1/2×（2sinxcosx）cos2x =1/2sin2xcos2x 二倍角公式 =1/4（2sin2xcos2x）=（sin4x）/4
sinxcosxcos2x =1/2×（2sinxcosx）cos2x =1/2sin2xcos2x 二倍角公式 =1/4（2sin2xcos2x）=（sin4x）/4
sinxcosxcos2x =1/2X(2sinxcosx)cos2x =1/2sin2xcos2x =1/4sin4x
sinxcosxcos2x=1/2sin2xcos2x=1/4sin4x
积化和差公式：sinxcosx=-1/2*cos2x*cos0 = -1/2cos2x sinxcosxcos2x = -1/2cos2x*cos2x = -1/2cos2x^2
sinxcosxcos2x =1/2*2sinxcosxcos2x =1/2*sin2xcos2x =1/4*2sin2xcos2x =1/4*sin4x =sin4x/4 【中学生数理化】团队为您解答！祝您学习进步 不明白可以追问！满意请点击下面的【选为满意回答】按钮，O(∩_∩)O谢谢
sinx cosx cos2x =0.5(2sinxcosx)cos2x =0.5(sin2xcos2x)=0.5×0.5sin4x =(1/4)×sin4x