(sin ^2(-θ )-cos ^2(-θ ))(sin (-θ )-cos (-θ ))=([sin (-θ )]^2-[cos (-θ )]^2)(sin (-θ )-cos (-θ ))=((-sin θ )^2-(cos θ )^2)(-sin θ -cos θ )=((sin θ -cos θ )(sin θ +cos θ ))(-(sin θ +cos θ ))=cos θ -sin θ ...
解析 (sin ^2(-θ )-cos ^2(-θ ))(sin (-θ )-cos (-θ ))=([sin (-θ )]^2-[cos (-θ )]^2)(sin (-θ )-cos (-θ ))=((-sin θ )^2-(cos θ )^2)(-sin θ -cos θ )=((sin θ -cos θ )(sin θ +cos θ ))(-(sin θ +cos θ ))=cos θ -sin ...
This question is from the trigonometry and we have verify the given identity. We will use some simple trigonometric ratios to solve this question.Answer and Explanation: {eq}\Rightarrow \ sin(x)+cos(x)cot(x)=csc(x)\\ \text{Taking Left_hand Side}\\ \Rightarrow \ sin(x)+cos(x...
Enter a problem...Algebra ExamplesPopular ProblemsAlgebraVerify the Identity sec(2x)=1/(sin(x)^2-cos(x)^2)Step 1 The provided equation is not an identity. is not an identity
Example 2: If sin θ = 3/5, find sin2θ.Solution: We know that sin2θ = 2 sin θ cos θWe need to determine cos θ.Let us use the sin cos formula cos2θ + sin2θ = 1.Rewriting, we get cos2θ = 1 - sin2θ= 1-(9/25)cos2θ = 16/25...
Establish the identity cos + sin 0 = cos 0 - sino -1- coto 1 + tan 0 Write the left side in terms of sine and cosine. cos sin 0 1 + Write each term from the previous step as one fraction. cos 20 sin 0 - cos 0 (List the ...
sin2(θ2)=secθ-12secθ Use the appropriate power-reducing formula and rewrite the left side of the identity. 1-cosθ (Simplify your answer.) Rewrite the expression from the previous step by multiplying the numerator and denominator by secθ...
这是三角恒等式（Trigonometric Identity）之一，表示正弦角 $a$ 的平方加上余弦角 $a$ 的平方等于 $1$，即：\sin^2 a + \cos^2 a = 1 这个恒等式也被称为“勾股定理”或“单位圆上任意一点到圆心的距离平方等于其横坐标平方与纵坐标平方的和”。
$$\sin \left(A - B \right) = \sin A \cos B - \cos A \sin B $$ Answer and Explanation: Given Data: Identity: {eq}\sin \left(\frac{\pi }{2}- \theta \right)=\cos \left( \theta \right) {/eq} Let us verify the identity: ...
Because the two sides have been shown to beequivalent, theequationis anidentity. cos2(x)1+sin(x)=1−1csc(x)cos2(x)1+sin(x)=1-1csc(x)is anidentity cos2(x)1+sin(x)=1−1csc(x)cos2(x)1+sin(x)=1-1csc(x) ...