Because the two sides have been shown to beequivalent, theequationis anidentity. cos2(x)1+sin(x)=1−1csc(x)cos2(x)1+sin(x)=1-1csc(x)is anidentity cos2(x)1+sin(x)=1−1csc(x)cos2(x)1+sin(x)=1-1csc(x) ...
Establish the identity: (sin ^2(-θ )-cos ^2(-θ ))(sin (-θ )-cos (-θ ))=cos θ -sin θ
2cos2(x)+sin(x)−1=02cos2(x)+sin(x)-1=0 Simplify2cos2(x)+sin(x)−12cos2(x)+sin(x)-1. Tap for more steps... Move-1. 2cos2(x)-1+sin(x)=0 cos(2x)+sin(x)=0 cos(2x)+sin(x)=0cos(2x)+sin(x)=0 Use thedouble-angleidentityto transformcos(2x)cos(2x)to1−...
Algebra Inputs Trigonometry Inputs Calculus Inputs Matrix Inputs ∫sin(θ)2cos(θ)dθ Evaluate 3(sin(θ))3+С Differentiate w.r.t. θ cos(θ)(sin(θ))2
代数输入 三角输入 微积分输入 矩阵输入 sin(x)2cos(y)2−cos(x)2sin(y)2 求值 sin(x−y)sin(x+y) 关于x 的微分 sin(2x)
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Question: Verify each identity.Problem 11-cos2xsin2x=tanx Verify each identity. Problem 1 1-cos2xsin2x=tanx There are 2 steps to solve this one. Solution Share Step 1 Explanation: let given equation is 1−cos2xsin2x=tanxView the full answer Step 2 Unlock Answer Unl...
这一公式实际上来源于三角恒等式中的Pythagorean Identity。这个恒等式告诉我们一个三角形的两条直角边的平方和等于斜边的平方。在这里，当我们将这一恒等式应用到单位圆上时，就得到了cos²α + sin²α = 1。从这个恒等式中，我们可以推导出cos2α的表达式为cos²&...
sin2(θ2)=secθ-12secθ Use the appropriate power-reducing formula and rewrite the left side of the identity. 1-cosθ (Simplify your answer.) Rewrite the expression from the previous step by multiplying the numerator and denominator by secθ...
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