(cotangent).sinθ=b/c cosθ=a/c tanθ=b/a cscθ=c/b secθ=c/a cotθ=a/b 三角恒等式 根据这些定义,可得到下列恒等式(identity):tanθ=sinθ/cosθ,cotθ=cosθ/sinθ secθ=1/cosθ,cscθ=1/sinθ 分别用cos 2θ与sin 2θ来除cos 2θ+sin 2θ=1,可得:sec 2θ–tan 2θ=1 及...
利用Pythagorean identity(勾股恒等式): [ \sin^2(x) + \cos^2(x) = 1 ] 由此,我们可以解出cos(x)或sin(x): [ \cos(x) = \pm \sqrt{1 - \sin^2(x)} ] [ \sin(x) = \pm \sqrt{1 - \cos^2(x)} ] 注意,这里的正负号取决于x所在的象限。 利用互余角的关系: 对于任意角x,其互...
根据这些定义,可得到下列恒等式(identity):tanθ=sinθ/cosθ,cotθ=cosθ/sinθ secθ=1/cosθ,cscθ=1/sinθ 分别用cos 2θ与sin 2θ来除cos 2θ+sin 2θ=1,可得:sec 2θ–tan 2θ=1 及 csc 2θ–cot 2θ=1 对于负角度,六个三角函数分别为:sin(–θ)=–sinθ csc(–θ)=–cscθ cos...
Tap for more steps... sin(x)cos(x)cos(x) Cancel theofcos(x). sin(x) sin(x)sin(x) Because the two sides have been shown to beequivalent, theequationis anidentity. tan(x)sec(x)=sin(x)tan(x)sec(x)=sin(x)is anidentity
This question is from the trigonometry and we have verify the given identity. We will use some simple trigonometric ratios to solve this question. Answer and Explanation: {eq}\Rightarrow \ sin(x)+cos(x)cot(x)=csc(x)\ \text{Taking Left_hand Side}\ \Rightarrow \ sin(x)+cos(x...
We have to prove the given trigonometric identity. Using the difference identity for cosine function we have that: $$\begin{align} \dfrac{\cos(x-y)...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our expe...
pythagorean identity: sinθ and cosθ sin²θ+cos²θ=1 pythagorean identity: tanθ and secθ tan²θ+1=sec²θ pythagorean identity: cotθ and cscθ 1+cot²θ=csc²θ sin30° 1/2 cos30° √3/2 tan30° √3/3 cot30° ...
通过代入sin和cos的定义,我们可以得到以下关系: sin^2 + cos^2 = (对边^2 + 邻边^2) / 斜边^2 = 1 这个等式被称为三角恒等式(trigonometric identity),它表明在任何直角三角形中,sin的平方加上cos的平方等于1。 3.2 tan与sin、cos的关系 根据tan和sin、cos的定义,我们可以得到以下关系: tan = 对边 ...
Verify the identity. cos^2 x - sin^2 x = cos 8x cos 6x + sin 8x sin 6x Verify the identity (1 + \tan^2 u) (1 - \sin^2 u) = 1 Verify the identity. tan^2 x - sin^2 x = (tan x sin x)^2 Verify the following identity. cos^2 x (sec^2 x - 1)...