I've got a rather large list that contains many dataframes of the same length. I'd like to rename all the column names in the list. I've tried to usepurrr::map, but have hit various issues. Is there a better way to do this? Here is areprexof the approach and issues I'm havi...
Console output: Errorin`colnames<-`(`*tmp*`,value=`*vtmp*`):attempt to set'colnames'on an object with less than two dimensions Expected Output names(df)[1]"Order""Answer""Names""D""E" Is there any other way to accomplish this?
library(msigdbr) h.human <- msigdbr(species = "Homo sapiens", category = "H") h.names <- unique(h.human$gs_name) h.sets <- vector("list", length = length(h.names)) names(h.sets) <- h.names library(dplyr) for (i in names(h.sets)) { h.sets[[i]] <- pull(h.human[h...
..- attr(*, "names")= chr "3" - attr(*, ".internal.selfref")=<externalptr> My best guess is that dplyr stores the column as a list of list, while data.table stores it simply as a list. This matches with the output you get from wrapping data.table on the output of the dplyr...
)) %>% purrr::set_names(levels(msigdb.go.bp$geneset)) # convert to list[KEGG] required by irGSEA package msigdb.kegg <- msigdb %>% dplyr::filter(collection=="C2:CP:KEGG_MEDICUS") %>% dplyr::select(c("geneset", "symbol")) msigdb.kegg$geneset <- factor(msigdb.kegg$geneset) ...
If you’ve managed to produce a 0-row data frame, dplyr won’t try to print the data, but will tell you the column names and types: data_frame(x=numeric(),y=character())#> Source: local data frame [0 x 2]#>#> Variables not shown: x (dbl), y (chr) ...
## colData names(4): Cell Batch Group ExpLibSize ## reducedDimNames(0): ## mainExpName: NULL ## altExpNames(0): colData(sim.groups) #The colData column 'Group' contains the groups of simulated cells ## DataFrame with 5000 rows and 4 columns ...
I am new to R and this is my first question on stackoverflow. I am trying to assign by reference to a new column for each row using the value from the first next row within the same group of rows that meets a condition. Example data: ...
library(dplyr)library(tidyr)library(purrr)library(stringr)columna_dummy<-function%>%(=1,rn=row_number())%>%pivot_wider(names_from=all_of(),values_from=,values_fill0)%>%select(-rn)} -testing For more than one column, an option is to loop over the column names of interest withmap,...
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