1. Search in Rotated Sorted Array Suppose an array sorted in ascending order is rotated(轮流,循环) at some pivot(枢轴; 中心点) unknown to you beforehand(提前; 事先). (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in th...
题目链接:https://leetcode.com/problems/search-in-rotated-sorted-array/题目: Suppose a sorted array is rotated at some pivot unknown to you beforehand. 0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, o...
LeetCode系列(六)- Search in Rotated Sorted Array 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组[0,1,2,4,5,6,7]可能变为[4,5,6,7,0,1,2])。 搜索一个给定的目标值,如果数组中存在这个目标值,则返回它的索引,否则返回-1。 你可以假设数组中不存在重复的元素。 你的算法...
LeetCode-33-搜索旋转排序数组(Search in Rotated Sorted Array) 33. 搜索旋转排序数组[https://leetcode-cn.c...
Leetcode 33. Search in Rotated Sorted Array Search in Rotated Sorted Array 题目大意:给定一个有序数组,经过旋转得到新得数组,也即改变起点位置,如[0,1,2,4,5,6,7] 变成[4,5,6,7,0,1,2]。要求仍然在log的时间进行查找某个特定的target...
[ 4 5 6 7 1 2 3] ,如果 target = 2,那么数组可以看做 [ -inf -inf - inf -inf 1 2 3]。 和解法一一样,我们每次只关心 mid 的值,所以 mid 要么就是 nums [ mid ],要么就是 inf 或者 -inf。 什么时候是 nums [ mid ] 呢?
此时medium = 3,正中间的数是0,根据情况2的提示,我们先判断到nums[low] = 4 是比nums[medium] = 0大的,说明旋转升序的起始点,这里是位置3,包含这low到medium之间,所以才会出现这种情况,同时这种情况也说明了,从medium到high之间的数,肯定是升序的,即Subnums2 = nums[medium to high]是升序数组,如果nums[...
Example 1: Input: nums = [2,5,6,0,0,1,2], target = 0 Output: true Example 2: Input: nums = [2,5,6,0,0,1,2], target = 3 Output: false Noted that: The array may contain dumplicated value, so this is different to Leet Code 33. Search in Rotated Sorted Array In the ...
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108. 将有序数组转换为二叉搜索树 - 给你一个整数数组 nums ,其中元素已经按 升序 排列,请你将其转换为一棵 平衡 二叉搜索树。 示例 1: [https://assets.leetcode.com/uploads/2021/02/18/btree1.jpg] 输入:nums = [-10,-3,0,5,9] 输出:[0,-3,9,-10,null,5] 解