Given an arraynums, returntrueif the array was originally sorted in non-decreasing order, then rotatedsomenumber of positions (including zero). Otherwise, returnfalse. There may beduplicatesin the original array. Note:An arrayArotated byxpositions results in an arrayBof the same length such tha...
LeetCode上牵扯到Rotated Sorted Array问题一共有四题,主要是求旋转数组的固定值或者最小值,都是考察二分查找的相关知识。在做二分查找有关的题目时,需要特别注重边界条件和跳出条件。在做题的过程中,不妨多设几个测试案例,自己判断一下。 下面是这四题的具体解答。 33.Search in Rotated Sorted Array 在求旋转...
Search in Rotated Sorted Array I && II Leetcode 对有序数组进行二分查找(下面仅以非递减数组为例): 1. int binarySort(int A[], int lo, int hi, int target) 2. { 3. while(lo <= hi) 4. { 5. int mid = lo + (hi - lo)/2; 6. if(A[mid] == target) 7. return mid; 8....
Suppose a sorted array is rotated at some pivot unknown to you beforehand. 0 1 2 4 5 6 7might become4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. 思路: ...
力扣leetcode-cn.com/problems/search-in-rotated-sorted-array-ii/ 题目描述 已知存在一个按非降序排列的整数数组 nums ,数组中的值不必互不相同。 在传递给函数之前,nums 在预先未知的某个下标 k(0 <= k < nums.length)上进行了 旋转 ,使数组变为 [nums[k], nums[k+1], ..., nums[n-1],...
This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。
今天分享leetcode第10篇文章,也是leetcode第154题—Find Minimum in Rotated Sorted Array II(寻找旋转排序数组中的最小值II),地址是:https://leetcode.com/problems/find-minimum-in-rotated-sorted-array-ii/ 【英文题目】(学习英语的同时,更能理解题意哟~) ...
}else{if(A[left] <= target && A[mid] > target) right = mid -1;elseleft = mid +1; } }return-1; } }; 本文转自博客园Grandyang的博客,原文链接:在旋转有序数组中搜索[LeetCode] Search in Rotated Sorted Array
This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。
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