bool searchMatrix(vector<vector<int> > &matrix, int target) { if(matrix.size() == 0) return false; int m = matrix.size(); int n = matrix[0].size(); if(target < matrix[0][0] || target > matrix[m-1][n-1]) //目标元素不在矩阵中 return false; int low = 0, high = m ...
if (target < matrix[mid][0]) { right = mid; } else if (target > matrix[mid][0]) { left = mid; } else { return true; } } left = 0; right = matrix[0].length - 1; while (left <= right) { //搜索在那一列 mid = left + (right - left) / 2; if (target < matrix[...
来自专栏 · LeetCode 每日一题 题意 给定一个 m * n 的整数矩阵 matrix ,每一行从左到右升序,每一行的第一个数字比上一行的最后一个数字大,判断 target 是否在这个矩阵中? 数据限制 m == matrix.length n == matrix[i].length 1 <= m, n <= 100 -(10 ^ 4) <= matrix[i][j], target <...
如果target是和matrix[i][n-1]比较来确定target所在行的话,则上面代码注释地方恰好要使用matrix[above]了: classSolution {public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {if(matrix.empty() || matrix[0].empty())returnfalse;if(target < matrix.front().front() || target > matrix....
【leetcode】Search a 2D Matrix Search a 2D Matrix Write an efficient algorithm that searches for a value in anmxnmatrix. This matrix has the following properties: Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the ...
matrix = [] for row in in_line[1].strip()[1: -4].split(']')[:-1]: matrix.append([int(n) for n in row.split('[')[1].split(',')]) k = int(in_line[2]) # print(matrix, k) print(obj.kthSmallest(matrix, k)) ...
Write an efficient algorithm that searches for a value in anmxnmatrix. This matrix has the following properties: Integers in each row are sorted in ascending from left to right. Integers in each column are sorted in ascending from top to bottom. ...
publicclassSolution{/* https://leetcode.com/discuss/48852/my-concise-o-m-n-java-solution */publicbooleansearchMatrix(int[][]matrix,inttarget){if(matrix==null||matrix.length<1||matrix[0].length<1){returnfalse;}introw=0,col=matrix[0].length-1;while(row<matrix.length&&col>=0){// star...
You are given anm x ninteger matrixmatrixwith the following two properties: Each row is sorted in non-decreasing order. The first integer of each row is greater than the last integer of the previous row. Given an integertarget, returntrueiftargetis inmatrixorfalseotherwise. ...
大家可以看完讲义结合 LeetCode Book 二分查找练习一下 问题定义 给定一个由数字组成的有序数组 nums,并给你一个数字 target。问 nums 中是否存在 target。如果存在, 则返回其在 nums 中的索引。如果不存在,则返回 - 1。 这是二分查找中最简单的一种形式。当然二分查找也有很多的变形,这也是二分查找容易出错...