Can you solve this real interview question? Search a 2D Matrix - You are given an m x n integer matrix matrix with the following two properties: * Each row is sorted in non-decreasing order. * The first integer of each row is greater than the last int
如果target是和matrix[i][n-1]比较来确定target所在行的话,则上面代码注释地方恰好要使用matrix[above]了: classSolution {public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {if(matrix.empty() || matrix[0].empty())returnfalse;if(target < matrix.front().front() || target > matrix....
class Solution: def searchMatrix(self, matrix: List[List[int]], target: int) -> bool: # 矩阵行数 m: int = len(matrix) # 矩阵列数 n: int = len(matrix[0]) # 二分区间左边界初始化为 0 l: int = 0 # 二分区间右边界初始化为 m * n - 1 r: int = m * n - 1 # 当二分...
*@return*/publicbooleansearchMatrix(int[][] matrix,inttarget) {if(matrix ==null)returnfalse;introw =matrix.length;if(row == 0)returnfalse;if(matrix[0] ==null)returnfalse;intcolumn = matrix[0].length;if(column == 0)returnfalse;if(target < matrix[0][0] && target > matrix[row - 1...
int n = matrix[0].size(); if(target < matrix[0][0] || target > matrix[m-1][n-1]) //目标元素不在矩阵中 return false; int low = 0, high = m - 1;//在行间和行内查找时共用这两个元素,表示当前查找的子范围 int medium; ...
https://leetcode.com/problems/search-a-2d-matrix/ 题目: m x n Integers in each row are sorted from left to right. The first integer of each row is greater than the last integer of the previous row. For example, Consider the following matrix: ...
LeetCode 240. Search a 2D Matrix II 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending ...
length-1; while(left<right){ int mid=(left+right)/2; if(matrix[row][mid]==target) return true; if(matrix[row][mid]>target) right=mid-1; else left=mid+1; } return matrix[row][left]==target; } public boolean searchMatrix(int[][] matrix, int target) { int m=matrix.length; ...
class Solution { public: bool searchMatrix(vector<vector<int> > &matrix, int target) { int rows = int(matrix.size()); int row = 0; bool flag = false;//标志是否有某一行的第一个数字比给定的数字大 for (int i = 0; i < rows; ++i) { if (matrix[i][0] == target) return tru...
/* * @lc app=leetcode id=240 lang=javascript * * [240] Search a 2D Matrix II * * https://leetcode.com/problems/search-a-2d-matrix-ii/description/ * * *//** * @param {number[][]} matrix * @param {number} target * @return {boolean} */var searchMatrix = function (matrix, ...