func searchMatrix(matrix [][]int, target int) bool { // 矩阵行数 m := len(matrix) // 矩阵列数 n := len(matrix[0]) // 二分区间左边界初始化为 0 l := 0 // 二分区间右边界初始化为 m * n - 1 r := m * n - 1 // 当二分区间至少还存在 2 个数时,继续二分 for l < ...
1、二分法查找代码如下: 1publicclassSolution {2publicbooleansearchMatrix(int[][] matrix,inttarget) {3if(matrix==null|| matrix.length==0 || matrix[0].length==0)4returnfalse;56intm =matrix.length;7intn = matrix[0].length;89intstart = 0;10intend = m*n-1;1112while(start<=end){13int...
classSolution {public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {if(matrix.empty() || matrix[0].empty())returnfalse;intm =matrix.size();intn = matrix[0].size();intleft =0, right = m * n -1;while(left <=right) {intmid = (left + right) >>1;inti = mid / n...
LeetCode 240. Search a 2D Matrix II 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties: Integers in each row are sorted in ascending ...
建议和leetcode 378. Kth Smallest Element in a Sorted Matrix 和 leetcode 668. Kth Smallest Number in Multiplication Table 有序矩阵搜索 代码如下: /* * 右上角搜索 * */ class Solution { public boolean searchMatrix(int[][] matrix, int target) ...
# Write an efficient algorithm that searches for a value in an m x n matrix. # This matrix has the following properties: # # Integers in each row are sorted from left to right. # The first integer of each row is greater than the last integer of the previous row. # For example, #...
length-1; while(left<right){ int mid=(left+right)/2; if(matrix[row][mid]==target) return true; if(matrix[row][mid]>target) right=mid-1; else left=mid+1; } return matrix[row][left]==target; } public boolean searchMatrix(int[][] matrix, int target) { int m=matrix.length; ...
编写一个高效的算法来搜索mxn矩阵matrix中的一个目标值target。该矩阵具有以下特性: 每行的元素从左到右升序排列。 每列的元素从上到下升序排列。 示例1: 输入:matrix = [[1,4,7,11,15],[2,5,8,12,19],[3,6,9,16,22],[10,13,14,17,24],[18,21,23,26,30]], target = 5输出:true ...
classSolution {publicbooleansearchMatrix(int[][] matrix,inttarget) {for(inti=0;i<matrix.length;i++){intleft=0;intright=matrix[0].length;while(left<right){intmid=left+(right-left)/2;if(matrix[i][mid]==target){returntrue; }elseif(matrix[i][mid]<target){ ...
hidden matrix 489.Robot-Room-Cleaner (H) 1778.Shortest-Path-in-a-Hidden-Grid (H-) 1810.Minimum-Path-Cost-in-a-Hidden-Grid (M+) BFS 127.Word-Ladder (M+) 126.Word-Ladder-II (M+) 130.Surrounded-Regions (H-) 200.Number-of-Islands (H-) 490.The-Maze (M) 529.Minesweeper (M+) ...