代码 classSolution {public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {if(matrix.size() ==0|| matrix[0].size() ==0)returnfalse; bottom=0, top = matrix[0].size() -1;for(inti =0; i < matrix.size(); ++i) {//对每一行进行二分查找boolf =binSearch(matrix[i], bott...
}if(matrix[x][y] ==target)returntrue; } Soltuion2: publicclassSolution {publicbooleansearchMatrix(int[][] matrix,inttarget) {if(matrix ==null)thrownewIllegalArgumentException("the reference of the matrix is null");if(matrix.length == 0 || matrix[0].length == 0)returnfalse;inty = ma...
1classSolution {2public:3boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {4intm = matrix.size(), n = matrix[0].size(), r =0, c = n -1;5while(r < m && c >=0) {6if(matrix[r][c] == target)returntrue;7if(matrix[r][c] > target) c--;8elser++;9}10returnfals...
从右上角開始, 比較target 和 matrix[i][j]的值. 假设小于target, 则该行不可能有此数, 所以i++; 假设大于target, 则该列不可能有此数, 所以j--. 遇到边界则表明该矩阵不含target. [CODE] public class Solution { public boolean searchMatrix(int[][] matrix, int target) { if(matrix.length==0...
classSolution { privatebooleanfind(int[][] matrix,inti,inttarget){ intleft=0,right=matrix[0].length-1; while(left<=right){ intmid=(left+right)/2; if(matrix[i][mid]==target)returntrue; elseif(matrix[i][mid]<target) left=mid+1; ...
LeetCode_240. Search a 2D Matrix II 题目描述: 思路:题目要求写一个高效率的算法,所以暴力遍历整个矩阵查找 的方法行不通了。 分析题目,发现这个矩阵是从左到右,从上到下递增的。可以发现矩阵右上角的元素是一个特殊的元素( ):如果 和 正好相等了,说明找到了。而当...
class Solution { public: bool searchMatrix(vector<vector<int>>& matrix, int target) { int m = matrix.size(); if(m<=0){ return false; } int n = matrix[0].size(); if(n<=0){ return false; } return searchMatrixHelper(matrix, 0, m-1, 0, n-1, target); ...
LeetCode 240. 搜索二维矩阵 II(Search a 2D Matrix II) 题目描述 编写一个高效的算法来搜索 m x n 矩阵matrix 中的一个目标值 target。该矩阵具有以下特性: 每行的元素从左到右升序排列。 每列的元素从上到下升序排列。 示例: 现有矩阵 matrix 如下: [ [1, 4, 7, 11, 15], [2, 5, 8, 12, ...
1"""2Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:3Integers in each row are sorted in ascending from left to right.4Integers in each column are sorted in ascending from top to bottom.5Example:6Consider the following ...
建议和leetcode 378. Kth Smallest Element in a Sorted Matrix 和 leetcode 668. Kth Smallest Number in Multiplication Table 有序矩阵搜索 代码如下: /* * 右上角搜索 * */ class Solution { public boolean searchMatrix(int[][] matrix, int target) ...