principle:1. iff matrix[x][y] >target, since y is sorted, target must not able to appear on y column, we should skip it.while( y >= 1 && target <matrix[x][y] ) { y--; }2. iff matrix[x][y] <target. since matrix[x][y-1] must smaller than it, and matrix[x][y+1]...
代码 classSolution {public:boolsearchMatrix(vector<vector<int>>& matrix,inttarget) {if(matrix.size() ==0|| matrix[0].size() ==0)returnfalse; bottom=0, top = matrix[0].size() -1;for(inti =0; i < matrix.size(); ++i) {//对每一行进行二分查找boolf =binSearch(matrix[i], bott...
因为matrix[i][j]小于所有>i 或>j的元素,也就是讲只有0~i 和0~j的元素无法确定大小。 算法: public boolean searchMatrix(int[][] matrix, int target) { int j = matrix[0].length-1,i=0; while(i<matrix.length&&j>=0){ if(matrix[i][j]>target){ j--; }else if(matrix[i][j]<targe...
建议和leetcode 378. Kth Smallest Element in a Sorted Matrix 和 leetcode 668. Kth Smallest Number in Multiplication Table 有序矩阵搜索 代码如下: /* * 右上角搜索 * */ class Solution { public boolean searchMatrix(int[][] matrix, int target) { if(matrix==null || matrix.length<=0) retur...
来自专栏 · LeetCode 每日一题 题意 给定一个 m * n 的整数矩阵 matrix ,每一行从左到右升序,每一行的第一个数字比上一行的最后一个数字大,判断 target 是否在这个矩阵中? 数据限制 m == matrix.length n == matrix[i].length 1 <= m, n <= 100 -(10 ^ 4) <= matrix[i][j], target <...
https://leetcode.com/problems/search-a-2d-matrix-ii/description/ 题解一 九章算法提供的比较巧妙的解题思路,从matrix 左下角开始向右上角遍历, 初始: introwIndex=matrix.length-1;intcolIndex=0; 逻辑主体: ifcurrentItem == target, return true; ...
Time Complexity: T(nxn) = 3T(n/2 x n/2) => O(3^logN) Space Complexity: O(logN) N = n^n Solution1 Code: classSolution1{publicbooleansearchMatrix(int[][]matrix,inttarget){if(matrix==null||matrix.length<1||matrix[0].length<1){returnfalse;}introw=0;intcol=matrix[0].length-1...
Can you solve this real interview question? Search a 2D Matrix II - Write an efficient algorithm that searches for a value target in an m x n integer matrix matrix. This matrix has the following properties: * Integers in each row are sorted in ascendin
Leetcode240. Search a 2D Matrix II搜索二维矩阵2 编写一个高效的算法来搜索 m x n 矩阵 matrix 中的一个目标值 target。该矩阵具有以下特性: 每行的元素从左到右升序排列。 每列的元素从上到下升序排列。 示例: 现有矩阵 matrix 如下: [ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, ...
240. Search a 2D Matrix II 题目描述 编写一个高效的算法来搜索 m x n 矩阵matrix 中的一个目标值 target。该矩阵具有以下特性: 每行的元素从左到右升序排列。 每列的元素从上到下升序排列。 每日一算法2019/6/9Day 37LeetCode240. Search a 2D Matrix II 示例: 现有矩阵 matrix 如下: [ [1, 4, ...