You are given therootof a binary search tree (BST) and an integerval. Find the node in the BST that the node's value equalsvaland return the subtree rooted with that node. If such a node does not exist, returnn
Insert Node in a Binary Search Tree Given a binary search tree and a new tree node, insert the node into the tree. You should keep the tree still be a valid binary search tree. Example Given binary search tree as follow, after Insert node 6, the tree should be: 22/ \ / \14--> ...
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
http://lintcode.com/zh-cn/problem/insert-node-in-a-binary-search-tree/ version 1: /** * Definition of TreeNode: * public class TreeNode { * public int val; * public TreeNode left, right; * public TreeNode(int val) { * this.val = val; * this.left = this.right = null; * ...
std::string to_string_in_order(void) const; int max_length_between_node(void) const;//最大节点距离 int height(void) const;//树高度 bool operator==(const binary_search_tree& other) const;//两个树相等:结构相同,对应元素相同 bool operator!=(const binary_search_tree& other) const { ...
the tree. You should keep the tree still be a valid binary search tree. Can you do it without recursion? 递归 /** * Definition of TreeNode: * class TreeNode { * public: * int val; * TreeNode *left, *right; * TreeNode(int val) { ...
定义:节点val值小于该节点val值并且值最大的节点 若一个节点有左子树,那么该节点的前驱节点是其左子树中val值最大的节点(也就是左子树中所谓的rightMostNode) 若一个节点没有左子树,那么判断该节点和其父节点的关系 2.1 若该节点是其父节点的右节点,那么该节点的前驱结点即为其父节点。 2.2 若该节点是其父节...
if node.data == data: return True, node, parent if node.data > data: return self.search(node.lchild, node, data) else: return self.search(node.rchild, node, data) # 插入 def insert(self, data): flag, n, p = self.search(self.root, self.root, data) ...
data + "->"); printInOrder(r.right); } public static class Node { private int data; private Node left; private Node right; public Node(int data) { this.data = data; } } public static void main(String[] args) { BinarySearchTree searchTree = new BinarySearchTree(); searchTree....
right;K_key;BSTreeNode(constK&key):_left(nullptr),_right(nullptr),_key(key){}};// class BinarySearchTreeNode - 树类template<classK>classBSTree{typedefBSTreeNode<K>Node;public:protected:Node*_root;};【说明】1BSTreeNode 类使用struct定义，其成员受默认访问限定符public修饰，BSTree 类能够直接...