Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
publicTreeNode searchBST(TreeNode root, intval) {if(root ==null|| root.val==val) {returnroot; } Queue<TreeNode> queue = new LinkedList<TreeNode>(); queue.offer(root);while(!queue.isEmpty()) { TreeNode temp = queue.poll();if(temp !=null&& temp.val==val) {returntemp; }elseif(...
inorder_tree_walk(p.right) def postorder_tree_walk(self, p): if p != None: self.inorder_tree_walk(p.left) self.inorder_tree_walk(p.right) print p.val 这里需要注意两点: 如果x 是一棵包含 n 个节点的子树,那么遍历该树的时间为 \Theta(n) . 中序遍历的结果必然是从小到大的排列 3. ...
insert(5); searchTree.insert(7); searchTree.printInOrder(searchTree.tree); // 1->2->3->4->5->6->7-> } } (二)、二叉查找树的查找操作 我们先取根节点,如果它等于我们要查找的数据,那就返回。如果要查找的数据比根节点的值小,那就在左子树中递归查找;如果要查找的数据比根节点的值大,那就...
1.Every node in the left subtree must be less than the current node 2.Every node in the right subtree must be greater than the current node Here the tree in Figure 2 is a binary search tree. Finding a data in a Binary Search Tree ...
right;K_key;BSTreeNode(constK&key):_left(nullptr),_right(nullptr),_key(key){}};// class BinarySearchTreeNode - 树类template<classK>classBSTree{typedefBSTreeNode<K>Node;public:protected:Node*_root;};【说明】1BSTreeNode 类使用struct定义，其成员受默认访问限定符public修饰，BSTree 类能够直接...
若p结点的左子树和右子树均不空:在删去p之后,为保持其它元素之间的相对位置不变,可按中序遍历保持有序进行调整,可以有两种做法 a. 令p的左子树为f的左/右(依p是f的左子树还是右子树而定)子树,s为p左子树的最右下的结点,而p的右子树为s的右子树 b. 令p的直接前驱(in-order predecessor)或直接后继(in...
python BinaryTree库文件 python binary search tree 1. 定义 二叉查找树(Binary Search Tree),又称为二叉搜索树、二叉排序树。其或者是一棵空树;或者是具有以下性质的二叉树: 若左子树不空,则左子树上所有结点的值均小于或等于它的根结点的值 若右子树不空,则右子树上所有结点的值均大于或等于它的根结点的值...
public void inOrder(){ inOrder(root); } // 中序遍历以node为根的二分搜索树, 递归算法 private void inOrder(Node node){ if(node == null) return; inOrder(node.left); System.out.println(node.e); inOrder(node.right); } // 二分搜索树的后序遍历 ...
(self, val): this.val = val this.left, this.right = None, None """ class Solution: """ @param root: The root of the binary search tree. @param node: insert this node into the binary search tree. @return: The root of the new binary search tree. """ def insertNode(self, root...