publicstaticintscoreOfString(String s){int num=0;for(int i=1;i<s.length();i++){num+=Math.abs(s.charAt(i)-s.charAt(i-1));}returnnum;} Runtime:1 ms, faster than100.00%of Java online submissions for Score of a String. Memory Usage:42 MB, less than50.00%of Java online submissio...
Score of a String/main.scala Original file line numberDiff line numberDiff line change @@ -0,0 +1,9 @@ object Solution { def scoreOfString(s: String): Int = { var sum: Int = 0 for (i <- 1 to s.length-1) { sum += (s.charAt(i-1) - s.charAt(i)).abs } return sum...
harsh-panchal-804 / LeetCode-Solutions Public Notifications Fork 0 Star 0 Code Issues Pull requests Actions Projects Security Insights Commits BreadcrumbsHistory for LeetCode-Solutions Score of a String.cpp onmain User selector All users DatepickerAll time Commit History End of commit ...
Runtime: 16 ms, faster than 94.77% of Python online submissions for Maximum Score After Splitting a String. Memory Usage: 13.4 MB, less than 65.70% of Python online submissions for Maximum Score After Splitting a String. 1 2 原题链接:https://leetcode.com/problems/maximum-score-after-split...
Can you solve this real interview question? Maximum Score After Splitting a String - Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring). The sco
(A) 得 2 * A 分,其中 A 是平衡括号字符串。 提示: S 是平衡括号字符串,且只含有 ( 和 ) 。 2 <= S.length &l...leetcode 856. Score of Parentheses(括号的分数) Given a balanced parentheses string s, return the score of the string. The score of a balanced parentheses string is ...
LeetCode Contest 186 5392. 分割字符串的最大得分 Maximum Score After Splitting a String Table of Contents 一、中文版 二、英文版 三、My answer 四、解题报告 一、中文版 给你一个由若干 0 和 1 组成的字符串 s ,请你计算并返回将该字符串分割成两个 非空 子字符串(即左 子字符串和 右 子字符串...
LeetCode 32. Longest Valid Parentheses Given astringcontaining just the characters '(' and ')', find the lengthofthe longest valid (well-formed)parenthesessubstring. Example 1: Example 2: 解法一:用栈stack 解法二:动态规划DP 【LeetCode】856. Score of Parentheses 解题报告(Python & C++) ...
classSolution{public:intscoreOfParentheses(string S){intres =0; stack<int> st;for(charc : S) {if(c =='(') { st.push(res); res =0; }else{ res = st.top() +max(res *2,1); st.pop(); } }returnres; } }; 我们可以对空间复杂度进行进一步的优化,并不需要使用栈去保留所有的中间...
The stringsconsists of characters'0'and'1'only. Accepted 45,173 Submissions 77,923 就是求左边0跟右边1的数字和哪个最大, 其实不用stringbuilder就可的,只是substring的 函数我还不太会,尴尬不尴尬。。。 classSolution{publicintmaxScore(String s){int max=0;int n=s.length();for(int i=0;i<s.le...