做到这题时卡了不少时间,参考了别人的解法,觉得挺不错的,还挺巧妙。 SELECTs2.Score,s1.RankFrom(SELECTS1.Score,COUNT(*)asRankFROM(SELECTDISTINCTScorefromScores)asS1, (SELECTDISTINCTScorefromScores)asS2WhereS1.Score<=S2.ScoreGroupByS1.Score ) s1 ,Scores s2WHEREs1.Score=s2.ScoreOrderBYs2.Scored...
LeetCode——Rank Scores Write a SQL querytorank scores.Ifthereisa tie between two scores, both should have the same ranking.Notethataftera tie, thenextranking number should be thenextconsecutiveintegervalue.Inother words, there should be no"holes"between ranks. +---+---+| Id | Score | ...
LeetCode: 178. Rank Scores 题目描述 Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be no “holes” be...
Leetcode-Rank Scores 技术标签: leetcode LeeCode上的database题目,Rank Scores。 # Write your MySQL query statement below set @rankNum=0; select Scores.Score, rank_t.Rank from Scores left join ( select score_t.Score, (@rankNum:=@rankNum+1) AS Rank from ( select distinct Score from...
LeetCode.178 Rank Scores 题目: Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer val......
【SQL刷题系列】:leetcode178 Rank Scores ▌题目描述 Write a SQL query to rank scores. If there is a tie between two scores, both should have the same ranking. Note that after a tie, the next ranking number should be the next consecutive integer value. In other words, there should be ...
selectScore,@i:=@i+(@pre<>(@pre:=Score))RankfromScores,(select@i:=0,@pre:=-1)initorderbyScoredesc 这里需要注意的是变量@pre。由于我们在权重那里判断是根据@pre(前一个score的值)是否等于当前score的值,如果@pre的初始值为大于0的数,就可能判断出错。最好@pre的初始值设置为小于0的数。
SELECTScore,@rank:=@rank+(@pre<>(@pre:=Score)) RankFROMScores, (SELECT@rank:=0,@pre:=-1) INITORDERBYScoreDESC; 参考资料: https://leetcode.com/discuss/40116/simple-short-fast LeetCode All in One 题目讲解汇总(持续更新中...)
leetcode178 分数排名 Rank Scores 编写一个SQL查询来实现分数排名。如果两个分数相同,则两个分数排名(Rank)相同。请注意,平分后的下一个名次应该是下一个连续的整数值。换句话说,名次之间不应该有“间隔”。 创建表和数据: CreatetableIfNotExistsScores (Idint,ScoreDECIMAL(3,2));TruncatetableScores;insert...
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