参考这个详细解答:https://discuss.leetcode.com/topic/77876/easy-java-solution-sorting publicclassSolution{publicString[] findRelativeRanks(int[] nums) {intpair[][] =newint[nums.length][2];for(inti=0; i < nums.length; i++) { pair[i][0] = nums[i]; pair[i][4] = i; } Arrays.so...
【leetcode】506. Relative Ranks problem 506. Relative Ranks solution1:使用优先队列; 掌握priority_queue和pair的使用; classSolution {public: vector<string> findRelativeRanks(vector<int>&nums) { priority_queue<pair<int,int>> myqueue;//for(inti=0; i<nums.size(); i++) { myqueue.push(pair(...
来自专栏 · leetcode_python_easy class Solution(object): def findRelativeRanks(self, nums): """ :type nums: List[int] :rtype: List[str] """ # nums排序后建立数字与对应排名的映射dict,然后利用dict对原nums取每个元素的排名 # sort = sorted(nums)[::-1] sort = sorted(nums, reverse=True...
AC Java: 1publicclassSolution {2publicString[] findRelativeRanks(int[] nums) {3int[][] pair =newint[nums.length][2];4for(inti = 0; i<nums.length; i++){5pair[i][0] =nums[i];6pair[i][1] =i;7}89Arrays.sort(pair, (a, b)->(b[0]-a[0]));10String [] res =newStrin...
参考这个详细解答:https://discuss.leetcode.com/topic/77876/easy-java-solution-sorting public class Solution { public String[] findRelativeRanks(int[] nums) { int pair[][] = new int[nums.length][2]; for (int i = 0; i < nums.length; i++) { ...
Relative Ranks Solution **解析:**Version 1,由于元素唯一,因此先对数组排序,然后构造有序数组与名次对应的字典,然后遍历数组得到对应的名词。...[mapping[score[i]] for i in range(n)] return result Reference https://leetcode.com/problems/relative-ranks ...
LeetCode算法题-Relative Ranks(Java实现) 这是悦乐书的第248次更新,第261篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第115题(顺位题号是506)。根据N名运动员的得分,找到他们的相对等级和得分最高的三个人,他们将获得奖牌:“金牌”,“银牌”和“铜牌”。例如:...
LeetCode Relative Ranks 原题链接在这里:https://leetcode.com/problems/relative-ranks/#/description 题目: Given scores of N athletes, find their relative ranks and the people with the top three highest scores, who will be awarded medals: "Gold Medal", "Silver Medal" and "Bronze Medal"....
详见:https://leetcode.com/problems/relative-ranks/description/ C++: classSolution{public:vector<string>findRelativeRanks(vector<int>&nums){intn=nums.size(),cnt=1;vector<string>res(n,"");map<int,int>m;for(inti=0;i<n;++i){m[nums[i]]=i;}for(autoit=m.rbegin();it!=m.rend();++it...
All the scores of athletes are guaranteed to be unique. 思路: 本题需要活用标准容器:pair及priority_queue,先维护pair数值对,统计nums[i]及对应下标,然后根据大顶堆来存储数据,最后再赋值(to_string) 代码: class Solution { public: vector<string> findRelativeRanks(vector<int>& nums) { ...