43 How Richard Feynman would solve this awesome golden integral【理查德·费曼将如何解决这个可怕的黄金】 13:42 Ahmed's monster integral solution using Feynman's technique【利用费曼技巧的艾哈迈德怪物积分解】 19:01 A RIDICULOUSLY AWESOME LOG INTEGRAL Integral of (ln(x))^2(x^2+1) from zero t ...
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DELTA MATH: Algebra 1 Linear Inequalities (Level 2) YouTube What Is a Constant in Algebraic Math? YouTube 更多視頻 相關概念 费根鲍姆常数 费根鲍姆常数是分岔理论中重要两个的数学常数,这两个常数因数学家费根鲍姆而得名。 第一费根鲍姆常数是倍周期分叉中相邻分叉点间隔的极限比率,用δ表示: δ=4.6692016...
printf("/t1.sin()/n"); printf("/t2.cos()/n"); printf("/t3.tan()/n"); printf("/t4.csc()/n"); printf("/t5.sec()/n"); printf("/t6.cot()/n"); printf("tEnter choice:"); scanf("%d",&ch); switch(ch){ case 1:{ ...
f(x)=sin(x)+cos(x-1) f(2) the parser automatically calculates sin(2)+cos(2-1) behind the scenes. Note, that such functions do not propagate to help. User hardcoded functions if you need more complex function, it is best to hardcode it and contribute it. However sometimes the mehto...
1/70+1/30=1/t One solution was found : t = 21 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ... 更多结果 共享 复制 已复制到剪贴板 示例 二次方程式 x2−4x−5=0 三角学 4sinθ...
syms x;s=0:0.01:22.05;eqn=(x-0.4677)/2+(sin(2*x)-sin(2*0.4677))/4-7*s/cos(0.4677)/493;solx = solve(eqn);
∂2u(x)∂xi2|xk≈∂u(x)∂xi|xk−∂u(x)∂xi|xk−vihi=u(xk+vi)−2u(xk)+u(xk−vi)hi2. With these definitions, we can approximate the Laplace equation at point xk, (2.45)∑i=1du(xk+vi)−2u(xk)+u(xk−vi)hi2=0, so we can solve for u(xk) and find...
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