publicclassSolution {/***@paramnum: a rotated sorted array *@return: the minimum number in the array*/publicintfindMin(int[] num) {if(num ==null|| num.length == 0)returnInteger.MIN_VALUE;intlb = 0, ub = num.length - 1;//case1: num[0] < num[num.length - 1]//if (num[l...
https://oj.leetcode.com/problems/find-minimum-in-rotated-sorted-array/ Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 解题...
public int findMin(int[] nums) { int start = 0; int end = nums.length - 1; while (start < end) { if (nums[start] < nums[end]) { return nums[start]; } int mid = (start + end) >>> 1; //必须是大于等于,比如 nums=[9,8],mid 和 start 都指向了 9 if (nums[mid] >=...
153. Find Minimum in Rotated Sorted Array 题目 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). Find the min element. You may assume no duplicate exists in the array. Example ...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. 0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 思路: 有序数组旋转后,如果mid元素比low大,则左边有序,右边乱序,考虑最左元素是否最小元素...
Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
Leetcode Link 示例1: Input: nums = [3,4,5,1,2] Output: 1 Explanation: The original array was [1,2,3,4,5] rotated 3 times. 示例2: Input: nums = [4,5,6,7,0,1,2] Output: 0 Explanation: The original array was [0,1,2,4,5,6,7]...
接Find Minimum in Rotated Sorted Array, 假设有重复数字。 Solution 解法依然是二分搜索,不过多了一种情况要考虑。 classSolution(object):deffindMin(self,nums):""" :type nums: List[int] :rtype: int """L,R=0,len(nums)-1whileL<Randnums[L]>=nums[R]:M=(L+R)/2ifnums[M]>nums[R]:...
Moreover, the minimum element spacing constraint for the synthesized array is considered by using an asymmetry mapping method (AMM). Importantly, on the basis of obtaining an equivalent or better pattern performance, the synthesized array can save 33.06% elements and avoid the usage of unequal ...
Find the minimum element. The array may contain duplicates. 这道题是Search in Rotated Sorted Array的扩展,思路在Find Minimum in Rotated Sorted Array中已经介绍过了,和Find Minimum in Rotated Sorted Array唯一的区别是这道题目中元素会有重复的情况出现。不过正是因为这个条件的出现,影响到了算法的时间复...