这样子即使是从未rotated的也没有关系,因为一直是丢右边的 直到余下左边最后2个。 View Code SOLUTION 4: 在解答3的基础之上先,预判断是不是旋转过,这样如果没有旋转我们可以直接把解算出即可。 View Code FOLLOW UP: LeetCode 新题: Find Minimum in Rotated Sorted Array II 解题报告-二分法模板解法 GitHub: GitHub代码链接
How and why? Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. The array may contain duplicates. 解法1:本题旋转数组最小值的扩展,这次数组中可以存在重复元素了。上题因数组中无重复...
154. Find Minimum in Rotated Sorted Array II 题目 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). Find the min element. The array may contain duplicates. Example 1: Input: [...
154. Find Minimum in Rotated Sorted Array II Follow up for “Find Minimum in Rotated Sorted Array”: What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i...
This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。
给定一个特殊升序数组,即一个排序好的数组,把前边的若干的个数,一起移动到末尾,找出最小的数字。 解法一 其实之前已经在 33 题 解法一中写过这个解法了,这里直接贴过来。 求最小值,遍历一遍当然可以,不过这里提到了有序数组,所以我们可以采取二分的方法去找,二分的方法就要保证每次比较后,去掉一半的元素。 这...
Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. The array may contain 仍然是在旋转有序数组中查找最小值,但是此时元素允许重复。有可能遇到如图所示的情况。
Notice thatrotatingan array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]. Given the sorted rotated array nums that may containduplicates, returnthe minimum element of this array. ...
详见:https://leetcode.com/problems/find-minimum-in-rotated-sorted-array-ii/description/ Java实现: class Solution { public int findMin(int[] nums) { int n=nums.length; int low=0; int high=n-1; int mid=0; while(nums[low]>=nums[high]){ if(high-low==1){ mid=high; break; } ...