https://oj.leetcode.com/problems/find-minimum-in-rotated-sorted-array/ Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum
Find Minimum in Rotated Sorted Array可以直接点击去看我对于旋转数组的分析。本题直接看代码 1publicclassSolution {2publicintfindMin(int[] num) {3intstart=0,end=num.length-1,mid=0;4while(start<end&&num[start]>=num[end]){5mid=(start+end)/2;6if(num[mid]>num[end])start=mid+1;7elseif...
This is a follow up problem to Find Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 描述 假设按照升序排序的数组在预先未知的某个点上进行了旋转。 ( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。 请找出其中最小的...
Follow up for “Find Minimum in Rotated Sorted Array”: What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 ...
This is a follow up problem toFind Minimum in Rotated Sorted Array. Would allow duplicates affect the run-time complexity? How and why? 题目大意 假设按照升序排序的数组在预先未知的某个点上进行了旋转。( 例如,数组 [0,1,2,4,5,6,7] 可能变为 [4,5,6,7,0,1,2] )。请找出其中最小的元...
给定一个特殊升序数组,即一个排序好的数组,把前边的若干的个数,一起移动到末尾,找出最小的数字。 解法一 其实之前已经在 33 题 解法一中写过这个解法了,这里直接贴过来。 求最小值,遍历一遍当然可以,不过这里提到了有序数组,所以我们可以采取二分的方法去找,二分的方法就要保证每次比较后,去掉一半的元素。 这...
Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. The array may contain duplicates. 思路: 寻找有序重复数组的最小值是对上一道题目的延伸,当数组中存在大量重...
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. The array may contain 仍然是在旋转有序数组中查找最小值,但是此时元素允许重复。有可能遇到如图所示的情况。
(比如 0 1 2 4 5 6 7 可能变成是 4 5 6 7 0 1 2)。找到其中最小的元素。数组中可能存在重复的元素。详见:https://leetcode.com/problems/find-minimum-in-rotated-sorted-array-ii/description/ Java实现: class Solution { public int findMin(int[] nums) { int n=nums.length; int low=0; ...