Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? 代码:oj测试通过 Runtime: 53 ms 1classSolution:2#@param matrix, a list of lists of integers3#@return a list of lists of integers4defrotate(self, matrix):5ifmatrixisNone:6returnNone7iflen(matrix[0])...
Python 解leetcode:48. Rotate Image 题目描述:把一个二维数组顺时针旋转90度; 思路: 对于数组每一圈进行旋转,使用m控制圈数; 每一圈的四个元素顺时针替换,可以直接使用Python的解包,使用k控制每一圈的具体元素; classSolution(object):defrotate(self, matrix):""" :type matrix: List[List[int]] :rtype:...
Rotate Image问题有哪些解法? 如何使用Python解决Leetcode的Rotate Image问题? 题目: You are given an n x n 2D matrix representing an image. Rotate the image by 90 degrees (clockwise). Follow up: Could you do this in-place? 思路分析: 最笨的方法,重新开辟一个矩阵空间,做旋转。(题目要求最好能...
LeetCode第48题:Rotate Image的解题思路是什么? 在LeetCode 48题中,如何实现图像的顺时针旋转90度? Problem 代码语言:javascript 代码运行次数:0 运行 AI代码解释 # You are given an n x n 2D matrix representing an image. # # Rotate the image by 90 degrees (clockwise). # # Note: # You have ...
class Solution: def rotate(self, matrix): """ :type matrix: List[List[int]] :rtype: void Do not return anything, modify matrix in-place instead. """ m = len(matrix) n = len(matrix[0]) for i in range(m): for j in range(i + 1): self.swap(matrix, i, j, j, i) for...
LeetCode Rotate Image LeetCode解题之Rotate Image 原题 将一个矩阵顺时针旋转90度。 注意点: 最好不要申请额外空间 样例: 输入: matrix = [[1, 2, 3], [8, 9, 4], [7, 6, 5]] 输出: [[7, 8, 1], [6, 9, 2], [5, 4, 3]]...
[Leetcode][python]Rotate Image/旋转图像 题目大意 顺时针翻转数组(以图像存储为例) 解题思路 先镜像反转,再每行前后翻转 代码 class Solution(object): def rotate(self, matrix): """ :type matrix: List[List[int]] :rtype: void Do not return anything, modify matrix in-place instead....
Can you solve this real interview question? Rotate Image - You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise). You have to rotate the image in-place [https://en.wikipedia.org/wiki/In-place_algorithm], whic
AI代码解释 classSolution{public:voidrotate(vector<vector<int>>&matrix){if(matrix.size()<=0)return;int a=0,b=matrix.size()-1;while(a<b){for(int i=0;i<b-a;++i){swap(matrix[a][a+i],matrix[a+i][b]);swap(matrix[a][a+i],matrix[b][b-i]);swap(matrix[a][a+i],matrix[...
代码(Python3) class Solution: def rotate(self, nums: List[int], k: int) -> None: """ Do not return anything, modify nums in-place instead. """ n: int = len(nums) # 计算最后有多少数字会被移动到数组开始 k %= n # 翻转整个数组 Solution.reverse(nums, 0, n - 1) # 翻转前 ...